Answer:
The answer D ...............
Answer:
Intensity of the transmitted radio wave is 5.406 x 10⁻⁶ W/m²
Explanation:
Given;
power of radio transmitter, P = 63.2 kW = 63200 W
distance of transmission, r = 30.5 km
Intensity of the transmitted radio wave is calculated as follows;
where;
I is the intensity of the transmitted radio wave
Substitute the given values and calculate the intensity of the transmitted radio wave;
Therefore, Intensity of the transmitted radio wave is 5.406 x 10⁻⁶ W/m²
Answer:
Explanation:
Li = 8.9 kg m² /s , Lf = 0
Time = Δt = 5.2 s
Angular impulse = change in angular momentum = Li - Lf
= 8.9 - 0 = 8.9 kg.m²/s .
Average torque = angular impulse / time
= 8.9 / 5.2 = 1.711 kg m² / s²
Li = 8.9 kg m² /s , Lf = 0
Δt = 5.2 s
unit of torque = force x distance = mass x acceleration x distance
= kg . m /s² x m
= kg m² / s²
Answer:
Oppositely charged objects attract each other
On Earth, the period of a pendulum is given by:
where L is the length of the pendulum and
is the gravitational acceleration on Earth.
Similarly, the period of the same pendulum on Mars will be
where
is the gravitational acceleration on Mars.
Therefore, if we want to see how does the period of the pendulum on Mars change compared to the one on Earth, we can do the ratio between the two of them:
Therefore, the period of the pendulum on Mars will be 1.63 times the period on Earth.