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geniusboy [140]
11 months ago
7

What would the length of segment BC have to be in order for line BC to be tangent to circle

Mathematics
1 answer:
Tju [1.3M]11 months ago
6 0

Given data:

The first given length is AC=53.

The second given length is AB= 45.

The expression for the Pythagoras theorem is,

\begin{gathered} AB^2+BC^2=AC^2 \\ (45)^2+BC^2=(53)^2 \\ BC^2=784 \\ BC=28 \end{gathered}

Here, consider only positive sign of BC length as side cannot negative.

Thus, the BC length is 28.

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GalinKa [24]

Answer:

30°

Step-by-step explanation:

Remember, all the interior angles of a triangle add up to 180 degrees. Therefore, we can find the value of x by subtracting the values of the other angles from 180:

x = 180-97-53

x=30

3 0
2 years ago
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I need answers asap... please
aleksandrvk [35]

Answer:

see explanation

Step-by-step explanation:

(4)

consider the left side

factor the numerator

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\frac{cosx(1-cos^2x)}{sinx}[/tex = [tex]\frac{cosxsin^2x}{sinx}

cancel sinx on numerator/denominator

= cosxsinx =right side ⇒ verified

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expand the factors

(1 + cotΘ)² + (1 - cotΘ)²

= 1 + 2cotΘ + cot²Θ + 1 - 2cotΘ + cot²Θ

= 2 + 2cot²Θ

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(6)

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the denominator simplifies to

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\frac{sin^2x(secx+cosecx)}{sinx}

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3 0
3 years ago
If a parking lot holds 1,600 cars and fills 3/4 of its spaces, how many spaces are filled?
AnnyKZ [126]

The total space in the parking lot is 1600 cars

It is mentioned that \frac{3}{4} parts of this parking is filled

Now we are required to find what is the three-fourths part of 1600

To find it we multiply \frac{3}{4} times 1600

\frac{3}{4}  X 1600

= \frac{3X1600}{4}

=\frac{4800}{4}

= 1200 cars

Hence 1200 cars fills the three-fourths of the car parking lot that has a capacity of 1600 cars

8 0
3 years ago
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2. How many real number solutions are there to the equation 0 =-3x2 + x - 4?
goblinko [34]

For this case we have the following quadratic equation:

-3x ^ 2 + x-4 = 0

Where:

a = -3\\b = 1\\c = -4

By definition, the discriminant of a quadratic equation is given by:

d = b ^ 2-4 (a) (c)

We have to:

d> 0: Two different real roots

dTwo different complex roots

d = 0: Two equal real roots

Substituting the values we have:

d = 1 ^ 2-4 (-3) (- 4)\\d = 1-48\\d = -47

So, we have two different complex roots

Answer:

Two different complex roots

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