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prohojiy [21]
3 years ago
12

A farmer grows two types of grain in his fields. He has a seed budget of $17,000.00 and has spent $9,200.00 to plant wheat seed

so far. If barley seed costs $41.00 per acre to plant, what is the maximum number of acres of barley the farmer can plant and still be under budget?
Mathematics
1 answer:
Helen [10]3 years ago
8 0
Okay so first you have to subtract 17000 from 9200 to see how much money you have left to spend. Then once you get that number, which is 7800, you have to see what's that maximum number of acres that you can get. So you divide 7800 from 41.00 and you can get your answer. Your answer will be 190 acres. 190 acres is the highest you can go without going over budget.
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1416

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When 15 times a number is.
lubasha [3.4K]

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2

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8 0
3 years ago
Solve the following systems of equations.<br> 2= 2y + 5<br> | 3y - 3x = -12
ivanzaharov [21]

Answer:

x=5/2, y=-3/2. (5/2, -3/2).

Step-by-step explanation:

2=2y+5

3y-3x=-12

--------------

2-5=2y

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3(-3/2)-3x=-12

-9/2-3x=-12

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3x=-9/2+24/2

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7 0
3 years ago
Which of the following is the solution to | x -12 | &lt; 15
KiRa [710]
Hello,
Answer D    -3<x<27
Indeed:
1)
if x-12≥0 then x≥12 and
|x-12|=x-12x-12<15 → x<27
so 12≤x<27
2) if x-12<0 then
x<12 and|x-12|=-(x-12)<15
-x+12<15-x<3 → x>-3
So -3<x<12
Thus -3<x<12  U 12≤x<27 ⇔ -3<x<27

7 0
3 years ago
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