Answer:
Step-by-step explanation:
The missing figure is shown in the attachment
The area of the shaded region = Area of Square - (Area of sector AOB + Area of equilateral triangle BOC + Area of sector COD)
Area of Sector AOB=Area of Sector COD=
Area of equilateral triangle =
Area of shade region =
64 miles per hour = x feet per second
Convert your units:
1 mile = 5280 feet
1 hour = 3600 seconds
64 miles/hour = 64(5280feet/3600seconds)
= 33792 feet / 3600 seconds = 9.386 feet / second
Therefore, 64 mi/h = 9.39 ft/s.
Answer:
At the time of launch height of the object was 60 meters.
Step-by-step explanation:
An object was launched from a platform and its height was modeled by the function,
h(x) = -5x² + 20x + 60
Where x = time or duration after the launch
At the time of launch, x = 0
So, by putting x = 0 in this equation,
h(0) = -5×(0) + 20×(0) + 60
h(0) = 60
Therefore, at the time of launch height of the object was 60 meters.
<h3>Solution for -3x+25=52 equation:</h3>
Simplifying
-3x + 25 = 52
Reorder the terms:
25 + -3x = 52
Solving
25 + -3x = 52
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-25' to each side of the equation.
25 + -25 + -3x = 52 + -25
Combine like terms: 25 + -25 = 0
0 + -3x = 52 + -25
-3x = 52 + -25
Combine like terms: 52 + -25 = 27
-3x = 27
Divide each side by '-3'.
x = -9
Simplifying
x = -9
Answer
263/999
Step-by-step explanation:
