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Len [333]
1 year ago
12

which of the following statements are true about client-side DNS? (Choose all that apply). a. If an APIPA address is assigned, t

hen DNS is the problem b. Client-side DNS should be configured to point towards the DNS server that is authoritative for the domain that client wants to join C.Check out DNS settings using the NSLookup command d.Check out DNS settings using the DIG command e.The cache.dns file has the IP addresses of the 13 root DNS servers f.If a web site can be reached by IP address and not by host name, then DNS or the Hosts file would be the problem
Engineering
1 answer:
Brums [2.3K]1 year ago
5 0

The statements which are true about client-side DNS include all of the following;

B. Client-side DNS should be configured to point towards the DNS server that is authoritative for the domain that client wants to join.

C. Check out DNS settings using the NSLookup command.

D. Check out DNS settings using the DIG command.

E. The cache.dns file has the IP addresses of the 13 root DNS servers.

B. If a web site can be reached by IP address and not by host name, then DNS or the Hosts file would be the problem.

<h3>What is a DNS server?</h3>

In Computer technology, a DNS server can be defined as a type of server that is designed and developed to translate domain names into IP addresses, so as to allow end users access websites and other internet resources through a web browser.

This ultimately implies that, a DNS server simply refers to a type of server that is designed and developed to translate requests for domain names into IP addresses for end users.

Read more on a domain names here: brainly.com/question/19268299

#SPJ1

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The tolerance for a geometric can be easily identified by reading the _________.
baherus [9]

Answer:

C

Explanation:

4 0
3 years ago
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A. A 3-kg plastic tank that has a volume of 0.2 m^3 is lled with liquid water. Assuming the density of water is 1000 kg=m^3, det
Tpy6a [65]

Answer:

The answer is below

Explanation:

a) The weight of the combined system is the sum of the weight of the water and the weight of the tank

m_{water}=V_{tank}.\rho_{wtaer}\\\\m_{water}=0.2m^3*1000kg/m^3\\\\m_{water}=200 \ kg\\\\m_{total} = m_{water}+m_{tank}\\\\But\ m_{tank}=3kg,therefore:\\\\m_{total} =200kg+3kg\\\\m_{total} =203\ kg\\\\weight_{total}=m_{total}g\\\\weight_{total}=203kg*9.81m/s^2\\\\weight_{total}=1991.43\ N

b) Since the weight of a system can be divided into smaller portions, hence weight is an extensive property.

c) When analyzing the acceleration of gases as they flow through a nozzle, the geometry of the nozzle which is an open system can be chosen as our system.

d) Given that:

\rho_{water}=1000kg/m^3\\\\1kg/m^3=0.062428lb/ft^3\\\\1000kg/m^3=1000kg/m^3*\frac{0.062428lb/ft^3}{kg/m^3}=62.43lb/ft^3\\ \\\rho=SG*\rho_{water}=1.03*62.43=64.272lb/ft^3\\\\P=P_{atm}+\rho g H\\\\P=14.7\ psia+64.272\ lb/ft^3*32.2\ ft/s^2*175\ ft*\frac{1\ ft^2}{12^2\ in^2}*\frac{1\ lbf}{32.2\ lbm.ft/s^2}  \\\\P=92.8\ psia

6 0
3 years ago
A circular column is fixed at the base and not supported at the top. If the column needs to be 15ft and hold 10kips, what is the
muminat

Answer:

The required size of column is length = 15 ft and diameter = 4.04 inches

Explanation:

Given;

Length of the column, L = 15 ft

Applied load, P = 10 kips = 10 × 10³ Psi

End condition as fixed at the base and free at the top

thus,

Effective length of the column, \L_e = 2L = 30 ft = 360 inches

now, for aluminium

Elastic modulus, E = 1.0 × 10⁷ Psi

Now, from the Euler's critical load, we have

P =\frac{\pi^2EI}{L_e^2}

where, I is the moment of inertia

on substituting the respective values, we get

10\times10^3 =\frac{\pi^2\times1.0\times10^7\times I}{360^2}

or

I = 13.13 in⁴

also for circular cross-section

I = \frac{\pi}{64}\times d^4

thus,

13.13 = \frac{\pi}{64}\times d^4

or

d = 4.04 inches

The required size of column is length = 15 ft and diameter = 4.04 inches

3 0
3 years ago
To be able to solve problems involving force, moment, velocity, and time by applying the principle of impulse and momentum to ri
coldgirl [10]

Answer:

see explaination

Explanation:

Please kindly check attachment for the step by step solution of the given problem.

The attached files has the solved problem.

3 0
3 years ago
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A long, horizontal, pressurized hot water pipe of 15cm diameter passes through a room where the air temperature is 24degree C. T
solmaris [256]

Answer:

Rate of heat transfer to the room air per meter of pipe length equals 521.99 W/m

Explanation:

Since it is given that the radiation losses from the pipe are negligible thus the only mode of heat transfer will be by convection.

We know that heat transfer by convection is given by

\dot{Q}=hA(T-T_{\infty })

where,

h = heat transfer coefficient = 10.45 W/m^{2}K (free convection in air)

A = Surface Area of the pipe

Applying the given values in the above formula we get

\dot{Q}=10.45\times \pi DL\times (130+273-(24+273))\\\\\frac{\dot{Q}}{L}=10.45\times 0.15\times \pi \times (130-24)\\\\\frac{\dot{Q}}{L}=521.99W/m

5 0
3 years ago
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