(35 points) This is a legit question that I have for a device FOR my homework.

MrRa [10]

That’s too hard for me lol oof

3 0

3 years ago

A vacuum gage connected to a chamber reads 35 kPa at a location where the atmospheric pressure is 92 kPa. The absolute pressure

Elodia [21]

Answer:

Absolute pressure= 57 KPa

Explanation:

Given that

Vacuum gauge pressure = 35 KPa

Atmospheric pressure = 92 KPa

We know that

Absolute pressure=Atmospheric pressure + gauge pressure

But we should remember that Vacuum gauge pressure is also called negative gauge pressure.So when given that pressure is vacuum gauge then subtract gauge pressure from atmospheric pressure instead of addition.

So now by putting the values

Absolute pressure=Atmospheric pressure - Vacuum gauge pressure

Absolute pressure=92 - 35 KPa

Absolute pressure= 57 KPa

7 0

3 years ago

. In a water cooling tower air enters at a height of 1 m above the ground level with velocity of 20 m/s and leaves the tower at

Zinaida [17]

Answer:

w ( mass flow rate of air ) = 3.16 kg/s

Explanation:

Determine the mass flow rate of air

mass flow rate of water = 1.5 kg/s

Height at which air enters the cooling tower = 1m

velocity of air entering at 1 m = 20 m/s

Height at which air leaves the cooling tower = 7 m

attached below is a detailed solution of the problem

4 0

3 years ago

Provide an argument justifying the following claim: The average (as defined here) of two Java ints i and j is representable as a

ahrayia [7]

Answer:

public static int average(int j, int k) {

return (int)(( (long)(i) + (long)(j) ) /2 );

}

Explanation:

The above code returns the average of two integer variables

Line 1 of the code declares a method along with 2 variables

Method declared: average of integer data type

Variables: j and k of type integer, respectively

Line 2 calculates the average of the two variables and returns the value of the average.

The first of two integers to average is j

The second of two integers to average is k

The last parameter ensures average using (j+k)/2

3 0

3 years ago

1. A cylindrical casting is 0.3 m in diameter and 0.5 m in length. Another casting has the same metal is rectangular in cross-se

Lorico [155]

Based on the Chvorinov's rule, the diference in the solidification times of the two castings is 14.092 times the solidification time of the prism casting.

<h3>How to apply the Chvorinov's rule for casting processes</h3>

The Chvorinov's rule is an empirical method to estimate the cooling time of a casting in terms of a reference time. This rule states that cooling time (t) is directly proportional to the square of the volume (V), in cubic meters, divided to the surface area (A), in square meters. Now we proceed to model each casting:

<h3>Cylindrical casting</h3>

t = C · [0.25π · D² · L/(0.5π · D² + π · D · L)]²

t = C · [0.25 · D · L/(0.5 · D + L)]² (1)

<h3>Prism casting</h3>

t' = C · [3 · T² · L/(6 · T · L + 2 · T · L + 6 · T²)]²

t' = C · [3 · T · L/(8 · L + 6 · T)]² (2)

<h3>Relationship between the cross sections of both castings</h3>

3 · T² = 0.25π · D² (3)

Where:

t - Cooling time of the cylindrical casting, in time unit.
t' - Cooling time of the prism casting, in time unit.
C - Cooling factor, in time unit per square meter.
D - Diameter of the cylinder, in meters.
L - Length of the casting, in meters.
T - Width of the cross section of the prism casting, in meters.

If we know that D = 0.3 m, then the thickness of the prism casting is:

$T = \sqrt{\frac{\pi}{12} }\cdot D$

T ≈ 0.153 m

And (1) and (2) simplified into these forms:

<h3>Cylindrical casting</h3>

t = C · {0.25π · (0.3 m) · (0.5 m)/[0.5 · (0.3 m) + 0.5 m]}²

t = 0.0329 · C (1b)

<h3>Prism casting</h3>

t' = C · {3 · (0.153 m) · (0.5 m)/[8 · (0.5 m) + 6 · (0.153 m)]}²

t' = 0.00218 · C (2b)

Lastly we find the percentual difference in the solidification times of the two castings by using the following expression:

r = (1 - t'/t) × 100 %

r = (1 - 0.00218/0.0329) × 100 %

r = 93.374 %

The cooling time of the prism casting is 6.626 % of the solidification time of the cylindrical casting. The diference in the solidification times of the two castings is 14.092 times the solidification time of the prism casting. $\blacksquare$

To learn more on solidification times, we kindly invite to check this verified question: brainly.com/question/13536247

3 0

3 years ago