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1 year ago

D. 240 in. 2. What is the surface area of this rectangular pyramid in

Mathematics

1 answer:

a_sh-v [17]1 year ago

6 0

Surface area of a rectangular pyramid = A + 1/2 p s

Where:

A = area of the base

p = perimeter of the base

s= salnt height = 5 in

A = Area of a rectangle = length x width = 8 x 4 = 32 in2

Perimeter of the base = 2 lenght + 2 width = 2(8)+2(4) = 24 in2

SA = 32 + 1/2 * 24 * 5 = 92 in2

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Answer:

<em>The building is 61.5 m tall</em>

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The image below is a diagram where all the given distances and angles are shown. We have additionally added some variables:

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a = 90° - 37° = 53°

b = 90° - 42° = 48°

Now we apply the tangent ratio on both triangles separately:

$\displaystyle \tan a=\frac{\text{opposite leg}}{\text{adjacent leg}}$

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From the last equation:

$x=h.\tan 48^\circ$

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$\displaystyle \tan 53^\circ=\frac{150-h.\tan 48^\circ}{h}$

Operating on the right side:

$\displaystyle \tan 53^\circ=\frac{150}{h}-\tan 48^\circ$

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$\displaystyle h=\frac{150}{\tan 53^\circ+\tan 48^\circ}$

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