Answer:
1.324
Step-by-step explanation:
Answer:
<em>consecutive </em><em>mult</em><em>iple</em><em> </em><em>of</em><em> </em><em>2</em><em> </em><em>is</em><em> </em><em>2</em><em>,</em><em>4</em><em>,</em><em>6</em><em> </em>
<em>this</em><em> </em><em>sum</em><em> </em><em>is</em><em> </em><em>2</em><em>+</em><em>4</em><em>+</em><em>6</em><em> </em><em>is</em><em> </em><em>1</em><em>2</em>
If the variables disappear and you get a statement that is never true,such as 0=5 or 4=7 then there is no solution meaning when graphed the two equations will form parallel lines which never interact
Given:
t A = 2.4 h
t B = 4 h
v A = 22 + v B
Solution:
Distance A and distance B is the same, distance could be defined using formula d = v × t
d A = d B
(v A × t A) = (v B × t B)
plug in the numbers
v A × 2.4 = v B × 4
(22 + vB) × 2.4 = 4 vB
remove the parenthesis using distributive property
(22 × 2.4) + (2.4 × vB) = 4vB
52.8 + 2.4vB = 4vB
add like terms
52.8 = 4vB - 2.4vB
52.8 = 1.6vB
52.8/1.6 = vB
vB = 33
the speed of car B is 33 mph
vA = 22 + vB
vA = 22 + 33
vA = 55
the speed of car A is 55 mph
