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Answer:
a factor of 2 is shown, but 4 was factored out
Step-by-step explanation:
The difference of squares is factored as ...
a² -b² = (a +b)(a -b)
Then the given difference of squares factors as ...
144x² -100 = (12x)² -10² = (12x +10)(12x -10)
Each of these factors has a factor of 2 that can be factored out:
= (2(6x +5))(2(6x -5))
= (2·2)(6x +5)(6x -5)
= 4(6x +5)(6x -5)
The first factor should be 4, not 2.
Answer:
Step-by-step explanation:
Start by factoring out a 5:
We need to find two integers that have a product of 12, and a sum of -7:
(-3)(-4)=12
-3-4=-7
We can split -7x into -3x and -4x
Factor each half separately:
![5[x(x-3)-4(x-3)]](https://tex.z-dn.net/?f=5%5Bx%28x-3%29-4%28x-3%29%5D)
Since x and -4 are both being multiplied by x-3, we can combine them:
Answer:
y = - 8x² + 6
Step-by-step explanation:
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
Here (h, k) = (0, 6), thus
y = a(x - 0)² + 6, that is
y = ax² + 6
To find a substitute (- 1, - 2) into the equation
- 2 = a(- 1)² + 6, that is
- 2 = a + 6 ( subtract 6 from both sides )
- 8 = a
y = - 8x² + 6
