Let width = w
Let length = l
Let area = A
3w+2l=1200
2l=1200-3w
l=1200-3/2
A=w*l
A=w*(1200-3w)/2
A=600w-(3/2)*w^2
If I set A=0 to find the roots, the maximum will be at wmax=-b/2a which is exactly 1/2 way between the roots-(3/2)*w^2+600w=0
-b=-600
2a=-3
-b/2a=-600/-3
-600/-3=200
w=200
And, since 3w+2l=1200
3*200+2l=1200
2l = 600
l = 300
The dimensions of the largest enclosure willbe when width = 200 ft and length = 300 ft
check answer:
3w+2l=1200
3*200+2*300=1200
600+600=1200
1200=1200
and A=w*l
A=200*300
A=60000 ft2
To see if this is max area change w and l slightly but still make 3w+2l=1200 true, like
w=200.1
l=299.85
A=299.85*200.1
A=59999.985
G>=5, so anything above or equal to 5 would count. So, you could use 5, 6, 7.
M = -9 ; solve for m by simplifying both sides of the equation, then isolating the varible
Answer:
I don't understand this Qu?estion
Step-by-step explanation:
Answer:
The equation of the line is;
y = 3x + 18
Step-by-step explanation:
We want to write the equation of the line through (-9,-9) and (-6,0)
we start by calculating the slope of the line
m = (y2-y1)/(x2-x1) = (0+ 9)/(-6+9) = 9/3 = 3
The general equation of the line is;
y = mx + c
y = 3x + c
To get c, we use any of the points
we substitute for example -6 for x and 0 for y
0 = 3(-6) + c
c = 0 + 18 = 18
So the equation of the line is;
y = 3x + 18
