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levacccp [35]
3 years ago
5

Complete the indirect proof to show that two supplementary angles cannot both be obtuse angles. given: angle1 and angle2 are sup

plementary. prove: angle1 and angle2 cannot both be obtuse. assume that two supplementary angles can both be obtuse angles. so, assume that angle1 and angle2 are obtuse. then mangle1 > 90° (equation 1) and mangle2 > ° (equation 2) by the definition of angles. adding the two inequalities, mangle1 + mangle2 > ° (equation 3). however, by the definition of supplementary angles, mangle1 + mangle2 = (equation 4). so equation 3 contradicts the given information. this means the assumption is , and therefore angle1 and angle2 both be obtuse.
Mathematics
1 answer:
AleksandrR [38]3 years ago
6 0

Two supplementary angles can never be both obtuse. To prove this, we use this example – consider two supplementary angles 60 degrees and 120 degrees. Sum of these two angles is 180 degrees. Here, the angle 120 degrees is an obtuse angle because obtuse angles are greater than 90 degrees. And since the angle 60 degrees is less than 90 degrees, it cannot be obtuse. Thus, the two supplementary angles cannot be both obtuse.

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Please help with this inequality.
iren [92.7K]
44\geq -3x + 2 > 14.
-2                                -2      -2

42\geq -3x > 12
-------------------------------------
-3                          -3       -3 (dividing with inequalities by a negative flips the inequality symbol)

-14\leq x < -4
3 0
3 years ago
A basketball team has 10 players. Before each game, the coach picks 2 of those players to carry the team's
labwork [276]

The different group of 2 players that the coach can pick is 45 groups.

<h3>Selection of groups</h3>

The selection of groups of 2 player can be done using the method of combination.

<h3>Different groups of 2 players</h3>

The different group of 2 players that the coach can pick from the 10 players is calculated as follows;

n = 10C2

n = \frac{10!}{(10-2)! 2!} = \frac{10 \times 9\times 8!}{8! \times 2} = 45

Thus, the different group of 2 players that the coach can pick is 45 groups.

Learn more about combinations here: brainly.com/question/25821700

6 0
2 years ago
You use 2 1/3 feet of string to make one bracelet. How many can you make with 10 1/2 feet of string?
Vesna [10]

Answer:4.5

Step-by-step explanation:

10 1/2÷2 1/3

5 0
3 years ago
Read 2 more answers
1/?=8/34 plz help i need this answer ASAP!!!
ehidna [41]

Answer:

1 / <u>4</u> = 8 / 34

1 * 32 = 8x

32 = 8x (divide both sides by 8)

4 = x

4 0
3 years ago
HELPPPPPPPPP AAAAAAAAA​
natali 33 [55]

Answer:

(5, -1)

Step-by-step explanation:

Equation 1:   3x + y = 14

Equation 2:   2x - 2y = 12

Rewrite equation 1 to make y the subject:

⇒ y = 14 - 3x

Substitute this into equation 2 and solve for x:

⇒ 2x - 2(14 - 3x) = 12

⇒ 2x - 28 + 6x = 12

⇒ 8x - 28 = 12

⇒ 8x = 40

⇒ x = 5

Substitute found value for x into either equation and solve for y:

using equation 1:

⇒ 3(5) + y = 14

⇒ 15 + y = 14

⇒ y = -1

Therefore, the solution to the system is (5, -1)

5 0
3 years ago
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