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Elina [12.6K]
1 year ago
8

Methanogenic bacteria convert acidic acid (CH3COOH) to CO2(g) and CH4(g)

Chemistry
1 answer:
Y_Kistochka [10]1 year ago
5 0

The enthalpy of the reaction can be obtained from the enthalpies of formation as  -16.2 kJ/mol.

<h3>What is the enthalpy of reaction?</h3>

We know that any time that there is a chemical  reaction, there is an interaction that place between the reactants and the products and as such we are going to get new substances and these are the substances that I have referred to here as the products of the reaction.

In this case, we are asked to obtain the enthalpy change of the reaction. This tells us the heat that could have been absorbed or evolved in the reaction. We have to at this point know that the enthalpy change of the reaction gotten from;

Sum of enthalpy of the products - Sum of enthalpy of the reactants

ΔH = [(-484.5)] - [(-393.5) + (-74.8)]

ΔH = (-484.5) + 468.3

ΔH = -16.2 kJ/mol

Learn more about enthalpy:brainly.com/question/3393755

#SPJ1

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What is the mass of an atom with seven protons, seven neutrons, and eight electrons?
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A plant extract can be obtained with organic solvents such as acetone or ethyl alcohol, and is composed of plant pigments such a
prohojiy [21]

Answer:

Here's what I get  

Explanation:

A plant extract is a mixture because it contains different substances: acetone or ethanol, chlorophylls A and B, carotene and xanthophylls.

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You can separate the pigments by paper, thin layer, or column chromatography.

Many schools use paper chromatography, because paper is cheap.

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3 years ago
After taking a hot shower you may notice that the room gets steamy and the mirror is foggy you might also notice that there is m
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3 years ago
By the reaction of carbon &amp; oxygen , a mixture of CO &amp;CO2 is obtained. What is the composition by mass of the mixture ob
Hatshy [7]
M(O₂)=20g
M(O₂)=32.0 g/mol
n(O₂)=20/32.0=0.625 mol

m(C)=12 g
M(C)=12.0 g/mol
n(C)=12/12.0=1.0 mol

   2C     +     O₂      →    2CO
1 mol    0.625 mol        1 mol
         0.625-0.5=0.125 mol

      2CO    +         O₂       →        2CO₂
0.250 mol       0.125 mol       0.250 mol

n(CO)=1 mol - 0.250 mol = 0.750 mol
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n(CO₂)=0.250 mol
M(CO₂)=44.0 g/mol
m(CO₂)=0.250*44.0=11.0 g
4 0
3 years ago
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