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cluponka [151]
3 years ago
13

The ksp for silver(i) phosphate is 1.8 x 10 –18 . determine the silver ion concentration in a saturated solution of silver(i) ph

osphate
Chemistry
1 answer:
mariarad [96]3 years ago
8 0
  The  silver  ion  concentration  in saturated  solution  of  silver (i) phosphate  is  calculated  as follows.

write  the  equation  for  dissociation of  silver (i)  phosphate
that  is  Ag3PO4 (s) =  3Ag^+(aq)   +  PO4 ^3-(aq)

let  the  concentration  of the  ion  be   represented  by  x
ksp  is  therefore=  (3x^3 )(x)  =  1.8  x10   ^-18

27 x^3 (x)  =  1.8  x10^-18
27x^4  =  1.8  x10^-18  divide both  side  27
X^4  =  6.67  x10  ^-20

find  the  fourth  root   x  =  1.6  x10 ^-5m

the  concentration  of  silver ion  is therefore = 3  x (1.6  x10^-5)  =  4.8  x10^-5m
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Consider the following reaction where Kc = 1.29×10-2 at 600 K: COCl2 (g) CO (g) + Cl2 (g) A reaction mixture was found to contai
vaieri [72.5K]

Answer:

1. In order to reach equilibrium COCl₂(g) must be consumed.

B. False

2. In order to reach equilibrium Kc must increase.

B. False .

3. In order to reach equilibrium CO must be consumed.

A. True.

4. Qc is greater than Kc.

A. True

5. The reaction is at equilibrium. No further reaction will occur.

B. False.

Explanation:

Based on the reaction:

COCl₂(g) → CO (g) + Cl₂(g)

And Kc is defined as:

Kc = 1.29x10⁻² = [CO] [Cl₂] / [COCl₂]

Molar concentrations of each species are:

[COCl₂] = 0.104 moles of COCl₂ / 1L = 0.104M

[CO] = 4.66×10⁻² moles of CO / 1L = 4.66×10⁻²M

[Cl₂] = 3.76×10⁻² moles of Cl₂ / 1L = 3.76×10⁻²M

Replacing in Kc formula:

4.66×10⁻²M × 3.76×10⁻²M / 0.104M = 1.68x10⁻²

As the concentrations are not in equilibrium, 1.68x10⁻² is defined as the <em>reaction quotient, Qc</em>.

As Qc > Kc, the reaction will shift to the left producing more COCl₂ and consuming CO and Cl₂. Thus

1. In order to reach equilibrium COCl₂(g) must be consumed.

B. False

2. In order to reach equilibrium Kc must increase.

B. False . Kc is a constant that never change.

3. In order to reach equilibrium CO must be consumed.

A. True.

4. Qc is greater than Kc.

A. True

5. The reaction is at equilibrium. No further reaction will occur.

B. False. The reaction is in equilibrium when Qc = Kc

6 0
4 years ago
When rubidium metal is exposed to air, two atoms of rubidium, Rb, combine with one atom
Eddi Din [679]

2.1653 g

Explanation:

The molar mass of Rubidium is;

85.468 g/mol

Therefore the moles of Rubidium that reacted with oxygen is;

1.98 / 85.468

= 0.0232 moles

If every two moles of Rubidium reacts with one mole of oxygen then the amount of oxygen consumed in the chemical reaction is;

0.5 * 0.0232

= 0.0116 moles

The molar mass of an oxygen atom is 16 g/mole. Then the amount of O in grams consumed is;

0.0116 * 16

=0.1853 g

The final weight of the Rubidium II Oxide is;

1.98 + 0.1853

= 2.1653 g

8 0
3 years ago
Is the following sentence true or false? The radius of an atom can be measured directly.
makkiz [27]
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3 0
3 years ago
Why does food need to be digested
OLga [1]

Answer:

Food has to be digested into smaller component nutrients that are then absorbed and used throughout your body. Calories in food provide your body with the energy it needs to complete vital processes such as cellular maintenance and reproduction, and respiration.

Explanation:

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5 0
3 years ago
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5. __HCl + __NaOH-&gt; __NaCl + __H2O
Dmitry_Shevchenko [17]

Answer:

5. balanced (1,1,1,1)(double replacement)

6. 1,2,1,1 (double replacement)

7. 1,3,2,2 (combustion)

Explanation:

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5 0
3 years ago
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