Question

The ksp for silver(i) phosphate is 1.8 x 10 –18 . determine the silver ion concentration in a saturated solution of silver(i) phosphate

Answer 1

  The  silver  ion  concentration  in saturated  solution  of  silver (i) phosphate  is  calculated  as follows.

write  the  equation  for  dissociation of  silver (i)  phosphate
that  is  Ag3PO4 (s) =  3Ag^+(aq)   +  PO4 ^3-(aq)

let  the  concentration  of the  ion  be   represented  by  x
ksp  is  therefore=  (3x^3 )(x)  =  1.8  x10   ^-18

27 x^3 (x)  =  1.8  x10^-18
27x^4  =  1.8  x10^-18  divide both  side  27
X^4  =  6.67  x10  ^-20

find  the  fourth  root   x  =  1.6  x10 ^-5m

the  concentration  of  silver ion  is therefore = 3  x (1.6  x10^-5)  =  4.8  x10^-5m