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Svetradugi [14.3K]
3 years ago
15

Which of the following is a chemical property of the noble gases?

Chemistry
2 answers:
notsponge [240]3 years ago
6 0

Answer:

have a full outer shell of electrons

Explanation:

Which of the following is a common property of Noble Gases?

Question 22 options:

1 seeks to donate one to three electrons

2 have a full outer shell of electrons

3 easily form chemical compounds

4 are highly reactive

5 are good conductors of electricity

Noble gases are the gases belonging to Group 18 of the periodic table. The electronic configuration for these gases are:

From the electronic configuration, it is visible that they have fully filled outer shell and hence, these gases are least reactive of all the elements in the periodic table.

As, they are not reactive and therefore they do not form any chemical compounds easily.  From the electronic configuration, it is visible that there are no free electrons in these gases, therefore, they are not good conductors of electricity.

Hence, the correct answer is that they all have full outer shell of electrons.

spin [16.1K]3 years ago
5 0
Noble gases are the elements located in the eighth group of the periodic table. These elements have the following properties:
They are odorless
They have single atoms (monoatomic)
They are colorless
They have very low chemical reactivity

The naturally occurring noble gases are helium, neon, argon, krypton, xenon and radon.
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Answer:

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Explanation:

2 C₄H₁₀ + 13 O₂ --> 8 CO₂ + 10 H₂O

To find the number of CO₂ molecules, you need to start with 100 grams of butane (C₄H₁₀), convert to moles (using the molar mass), convert to moles of CO₂ (using coefficients from equation), then convert to molecules (using Avagadro's number). The molar mass of C₄H₁₀ is calculated using the quantity of each element (subscript) multiplied by the number on the periodic table. The ratios should be arranged in a way that allows for units to be cancelled.

4(12.011g/mol) + 10(1.008 g/mol) = 58.124 g/mol C₄H₁₀

100 grams C₄H₁₀          1 mol C₄H₁₀             8 mol CO₂          
--------------------------  x  ----------------------  x  ---------------------  
                                        58.124 g              2 mol C₄H₁₀          

    6.022 x 10²³ molecules
x  ------------------------------------  =  4.14 x 10²⁴ molecules CO₂
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