Question

three fully discharged 1uf capacitors are placed in series and connected to a 100ua current source for 10 milliseconds. (a) what is the voltage across the series connected set? (b) what is the effective capacitance of the set? (c) what is the voltage across each individual capacitor?

Answer 1

A)  The voltage across the series connected set is 3V

B) The effective capacitance of the set is  $\frac{1}{3}$μF

C) The voltage across each individual capacitor is 1V

What is capacitance?

Capacitance is the property of an electric conductor or a set of conductors, which is measured by the amount of separated electric charge that may be stored on it per unit change in electrical potential.

The capacitance (C) is defined as the ratio of amount of charge(q) on either conductor to the potential difference (V) between the conductors

So, C = q/V.

According to the question,

C₁ = C₂ = C₃ = 1μF

I = 100μA

t = 10ms

Total capacitance (Cₓ) = $\frac{1}{3}$μF

I = $\frac{CV}{t}$

So Vₓ = $\frac{It}{C}$

Vₓ = 3V

Total effective capacitance(Cₓ) = $\frac{1}{3}$μF

Voltage across each individual capacitor(Vₓ) = V₁ + V₂ + V₃

$\frac{Vₓ}{3}$ = 1V

To know more about capacitance visit:

brainly.com/question/14746225

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