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DiKsa [7]
2 years ago
12

The force of attraction that a -40.0 μC point charge exerts on a +108 μC point charge has magnitude 4.00 N. How far apart are th

ese two charges? (k = 1/4πε0 = 8.99 × 109 N ∙ m2/C2)
Physics
1 answer:
Karolina [17]2 years ago
8 0

Answer:

F = k q1 q2 / r^2

r^2 = k q1 q2 / F  = 9E9 * 4E-5 * 10.8E-5 / 4

r^2 = 9 * 4 * 10.8 / 4 * E-1 = 9.72 m^2

r = 3.12 m

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I got part c right but idk why the other parts are wrong HELP!
dedylja [7]

a) The impulse is 76.5 Ns

b) The average force is 546.4 N

c) The final speed is 31.5 m/s

Explanation:

a)

The impulse exerted on an object is defined as

J=\int F\Delta t

where

F is the magnitude of the force exerted on the object

\Delta t is the time interval during which the force is applied

If we consider a graph of the force applied vs time, it follows that the impulse exerted is equal to the area under the graph.

Therefore, in this problem, we can calculate the impulse by computing the area under the graph. We have a trapezium, whose bases are

B=0.14-0 = 0.14s\\b=8-5=3s

and whose height is

h=900 N

Therefore, the area (and the impulse) is

J=\frac{(B+b)h}{2}=\frac{(0.14+0.03)(900)}{2}=76.5 Ns

b)

In this problem, the force applied is not constant. However, we can rewrite the impulse also as

J=F_{avg} \Delta t

where

F_{avg} is the average force exerted during the whole time \Delta t

In this problem we have

J = 76.5 Ns is the impulse (calculated in part a)

\Delta t = 0.14 s is the time interval

Solving for the average force, we find

\Delta t = \frac{J}{F_{avg}}=\frac{76.5}{0.14}=546.4 N

c)

According to the impulse theorem, the impulse exerted on an object is equal to the change in momentum of the object:

J=\Delta p = m(v-u)

where

m is the mass of the object

v is the final velocity

u is the initial velocity

In this problem, we have

J = 76.5 Ns

m = 3.0 kg is the mass

u = 6.0 m/s is the initial velocity

Solving for v, we find the final velocity (and speed):

v=u+\frac{J}{m}=6.0+\frac{76.5}{3}=31.5 m/s

Learn more about impulse and momentum:

brainly.com/question/9484203

#LearnwithBrainly

6 0
3 years ago
What is the law of conservation of energy?
charle [14.2K]
The law of conservation of energy<span>, a fundamental concept of physics, states that the total amount of </span>energy<span> remains constant in an isolated system. It implies that </span>energy<span> can neither be created nor destroyed, but can be change from one form to another.</span>
6 0
2 years ago
What do folds on a strip of paper mean
Vlad [161]
There are creases. Or just origami
7 0
2 years ago
A single conservative force Fx = (6.0x  12) N (x is in m) acts on a particle moving along the x axis. The potential energy asso
jasenka [17]

Answer:

U(3)=-43J

Explanation:

Potential energy is minus the integral of Fdx.  Doing the integration yields:

U=\int\limits {6.0x+12}\, dx

U=-3x^2-12x+C

U(0)=20J

so

U(0)=-3(0)^2+12(0)+C=20

C=20

Now for x=3.0m

U(3)=-3*(3)^2-12(3)+20

U(3)=-43J

6 0
3 years ago
Which of the following are physical properties of nonmetals? a. they are brittle in the solid form b. most are gases at room tem
Black_prince [1.1K]

Option (D) is correct that all of the above are physical properties of non metals.

#$# THANK YOU #$#

6 0
3 years ago
Read 2 more answers
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