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2 years ago

12

The force of attraction that a -40.0 μC point charge exerts on a +108 μC point charge has magnitude 4.00 N. How far apart are th

ese two charges? (k = 1/4πε0 = 8.99 × 109 N ∙ m2/C2)

1 answer:

Karolina [17]2 years ago

8 0

Answer:

F = k q1 q2 / r^2

r^2 = k q1 q2 / F = 9E9 * 4E-5 * 10.8E-5 / 4

r^2 = 9 * 4 * 10.8 / 4 * E-1 = 9.72 m^2

r = 3.12 m

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