1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Andre45 [30]
3 years ago
12

A hole is to be drilled in the plate at A. The diameters of the bits available to drill the hole range from 12 to 24 mm in 3-mm.

increments. Determine: (a) the diameter d of the largest bit that can be used if the allowable load at the hole is not to exceed that at the fillets.

Physics
1 answer:
blondinia [14]3 years ago
3 0

Answer:

The maximum load is when the hole size is 12 mm so the largest bit such that the load is not exceeding the P value is 12 mm.

Explanation:

As the question is not complete, the complete question is found online and is attached herewith.

From the given data

Allowable stress is given  as \sigma_{all}=145 MPa

Diameters of the bits are 12 mm, 15 mm, 18 mm, 21 mm, 24 mm

For the fillet, the dimensions are given in the attached question which are as

radius rf=9 mm

Small diameter d=75 mm

Large Diameter D=112.5 mm

The ratios of the diameters are calculated as

D/d=1.5

rf/d=0.12

So for these values and from the table, the value of K is found as 2.1

The area is given as

A=d*t

where d=75 mm, t=12 mm

A=75*12=900x10^-6 m2

Now the value of the average stress is given as

\sigma_{av}=\dfrac{\sigma_{max}}{K}\\P=\sigma_{av}A\\P=\dfrac{\sigma_{max} A}{K}\\P=\dfrac{145 \times 10^6 *900\times 10^{-6}}{2.1}\\P=62.1 kN

So for the various holes the value of r is the radius of the hole so

D=112.5 mm as given above whereas

d=D-2r

so the areas, value of k and respective values of P and σ are calculated for each radii and are attached with the solution.

As seen from the attached values, it is observed that the maximum load is when the hole size is 12 mm so the largest bit such that the load is not exceeding the P value is 12 mm.

You might be interested in
If a battery causes a wire to carry a current of 4 Amps how many coulombs of charge flow past any point in the wire in 3 seconds
BabaBlast [244]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

According to above question ~

  • Current (I) = 4 Amperes

  • Time (t) = 3 seconds

  • Charge (q) = ?

Let's find the charge (q) by using formula ~

  • I =  \dfrac{q}{t}

  • 4 =  \dfrac{q}{3}

  • q = 4 \times 3

  • q = 12 \:  \: coulombs

Hence, 12 coulombs of charge flow past any point in the wire in 3 seconds

7 0
3 years ago
ball of mass 0.4 kg is attached to the end of a light stringand whirled in a vertical circle of radius R = 2.9 m abouta fixed po
Levart [38]

Answer:

6.046N

Explanation:

The net force exerted on the mass is the sum of tension force and the external force of gravity.

F_n_e_t=F_g+F_t

F_t is the tension force.F_g=9.8N/kg is the force of gravity.

F_n_e_t=ma_c=mv^2/r\\

where r is the rope's radius from the fixed point.

From the net force equation above:

F_t=F_n_e_t-F_g\\=mv^2/r-mg\\=0.4\times(8.5^2/2.9)-0.4\times9.8\\=6.046N

Hence the tension force is 6.046N

8 0
3 years ago
Describe the motion of a swing that requires 6 seconds to complete one cycle. What is its period and the frequency? Round to the
shutvik [7]

Period = 6 seconds and frequency = 0.167Hz .

<u>Explanation:</u>

We have , the motion of a swing that requires 6 seconds to complete one cycle. Period is the amount of time needed to complete one oscillation . And in question it's given that 6 seconds is needed to complete one cycle. Hence ,Period of the motion of a swing is 6 seconds . Frequency is the number of vibrations produced per second and is calculated with the formula of  \frac{1}{t} . SI unit of frequency is Hertz or Hz. We know that time period is 6 seconds so frequency =   \frac{1}{t}

⇒ frequency = \frac{1}{time}

⇒ frequency = \frac{1}{6}

⇒ frequency = 0.167Hz

Therefore , Period = 6 seconds and frequency = 0.167Hz .

7 0
3 years ago
Light hits a mirror at a 45° angle. It will be reflected at an angle _____.
Eddi Din [679]
It will be equal to 45°
6 0
2 years ago
A projectile is shot on level ground with a
erastova [34]

Answer:

time rising = 34 / 9.8 = 3.47 sec

total time in air = 2 * 3.47 sec = 6.94 sec

(time rising must equal time falling)

R = 17 m/s * 6.94 s = 118 m

Can also use range formula

R = v^2 sin (2 theta) / g

tan theta = 34 / 17 = 2

theta = 63.4 deg

2 theta = 126.9 deg

sin 126.9 = .8

v^2 = 17^2 + 34^2 = 1445 m^2/s^2

R = 1445 * .8 / 9.8 = 118 m    agreeing with answer found above

5 0
2 years ago
Other questions:
  • A 65-cm segment of conducting wire carries a current of 0.35 A. The wire is placed in a uniform magnetic field that has a magnit
    13·2 answers
  • Which body exerts the force that propels the sprinter, the blocks or the sprinter?
    9·1 answer
  • A 70 kilogram mountaineer is standing on the summit of Mt. Everest. The distance between the mountaineer and the center of Earth
    9·2 answers
  • Dr. Martin Luther King, Jr., used which method to draw attention to the civil rights movement?
    15·1 answer
  • Hydraulic systems utilize Pascal's principle by transmitting pressure from one cylinder (called the primary) to another (called
    7·1 answer
  • . At what velocity will the box in Problem 6 be traveling when it hits the ground? Use formula: Va = Vf - Vi / 2
    12·1 answer
  • Providing that it does not collide with another object, what is the most likely reason that an object moving through space would
    5·1 answer
  • Which part of the wave has the highest frequency?
    13·2 answers
  • The weight of an object is the force pulling the object:
    13·1 answer
  • EX 6-1 A ball is twirled on a 0.870 - m-long string with a constant speed of 3.36 m / s . Calculate the acceleration of the ball
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!