3 years ago

When an unbalanced force acts on an object

Physics

1 answer:

xz_007 [3.2K]3 years ago

3 0

Answer:

D. The object accelerates

Explanation:

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In Millikan’s experiment, the oil droplets acquire one or more negative charges by combining with the negative charges that are

alina1380 [7]

Answer:

$-9.6\cdot 10^{-19} C$

Explanation:

The charge of a single electron is:

$q=-1.60\cdot 10^{-19} C$

If a droplet contains N electrons, then its charge would be:

$Q=Nq$

In this case, the droplet has

N = 6

electrons, so its total charge is

$Q=(6)(-1.60\cdot 10^{-19}C)=-9.6\cdot 10^{-19} C$

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3 years ago

9. In a __________ collision, 100% of both vehicles' speed is directed towards the point of impact. A. head-on B. rear-end C. si

Zepler [3.9K]

Answer: A

Explanation:

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3 years ago

What is charge measured in

Gre4nikov [31]

Charge is measured in coulombs.

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4 years ago

A rubber band that has been stretched has gained ____ energy

Dafna11 [192]

Answer: potential

Explanation:

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4 years ago

if change in blood pressure between the brain and the feet is 1.88×10^4 pa .what will be the volume flow rate from head to feet

klio [65]

Answer: $3765.66 \frac{m^{3}}{s}$

Explanation:

We can solve this problem using the <u>Poiseuille equation</u>:

$Q=\frac{\pi r^{4}\Delta P}{8\eta L}$

Where:

$Q$ is the Volume flow rate

$r=23 cm \frac{1 m}{100 cm}=0.23 m$ is the effective radius

$L=6 ft \frac{0.3048 m}{1 ft}=1.8288 m$ is the length

$\Delta P=1.88(10)^{4} Pa$ is the difference in pressure

$\eta=3(10)^{-3} Pa.s$ is the viscosity of blood

Solving:

$Q=\frac{\pi (0.23 m)^{4}(1.88(10)^{4} Pa)}{8(3(10)^{-3} Pa.s)(1.8288 m)}$

$Q=3765.66 \frac{m^{3}}{s}$

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4 years ago