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AveGali [126]
1 year ago
10

please look at the attached image i have to finish this entire unit by midnight and im stuck on this problem

Chemistry
1 answer:
djyliett [7]1 year ago
4 0
\text{H}_{2(g)}\text{ + CO}_{2(g)}\text{ }\rightleftarrows\text{ H}_2\text{O}_{(g)}\text{ + CO}_{(g)}

The reaction is balanced

The equilibrium constant is defined as the concentration ratio of the products and reactants. They are not considered pure solids and liquids.

\text{ K}_{eq}=\frac{\lbrack\text{CO}\rbrack\lbrack\text{ H}_2\text{O}\rbrack}{\lbrack\text{ H}_2\rbrack\lbrack\text{ CO}_2\rbrack}

So the answer is option B.

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3690 J of heat are added to a 21.5 g sample
Fiesta28 [93]

Answer:

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Explanation:

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ΔH in this case is 3690J.

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Explain how to calculate the density of a regular shaped object such as a rectangular box.
belka [17]

The density of a regular shaped object such as a rectangular box is calculated as thus:

The amount of matter is its mass, and the space it takes up is its volume.

So therefore, to calculate the density of an object such as the a regular shaped one like a rectangular box;

Its density = mass / volume.

<h3>Derived quantities</h3>

These are physical quantities which are obtained from fundamental quantities. I'm order words, derived quantities are quantities which are obtained from the combination of of fundamental quantities either by addition, division or multiplication

Some few examples of derived quantities are as follows:

Density

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So therefore, the density of a regular shaped object such as a rectangular box is calculated as thus:

The amount of matter is its mass, and the space it takes up is its volume.

So therefore, to calculate the density of an object such as the a regular shaped one like a rectangular box;

Its density = mass / volume.

Learn more about derived quantities:

brainly.com/question/28180944

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