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exis [7]
2 years ago
7

The bond between metal ions and the sea of electrons

Chemistry
1 answer:
Vilka [71]2 years ago
6 0

Answer: Metallic Bonding. ... In metallic bonds, the valence electrons from the s and p orbitals of the interacting metal atoms delocalize. That is to say, instead of orbiting their respective metal atoms, they form a “sea” of electrons that surrounds the positively charged atomic nuclei of the interacting metal ions.

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The electrolysis of water forms H2 and O2. 2H2O Right arrow. 2H2 O2 What is the percent yield of O2 if 10.2 g of O2 is produced
Mama L [17]

Answer:

67.5%

Explanation:

Step 1: Write the balanced equation for the electrolysis of water

2 H₂O ⇒ 2 H₂ + O₂

Step 2: Calculate the theoretical yield of O₂ from 17.0 g of H₂O

According to the balanced equation, the mass ratio of H₂O to O₂ is 36.04:32.00.

17.0 g H₂O × 32.00 g O₂/36.04 g H₂O = 15.1 g O₂

Step 3: Calculate the percent yield of O₂

Given the experimental yield of O₂ is 10.2 g, we can calculate its percent yield using the following expression.

%yield = (exp yield / theoret yield) × 100%

%yield = (10.2 g / 15.1 g) × 100% = 67.5%

8 0
3 years ago
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Katen [24]
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6 0
3 years ago
Which of the following statement(s) are true about the atoms of any element?
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6 0
3 years ago
Cesium-137 has a half life of 30.0 years. If initially there are 8.0 kg of cesium-137 present in a sample, how many kg will rema
viva [34]

Mass after 60 years:

2 kg of cesium-137 will remain after 60.0 years.

What is Half-life?

The duration needed for a quantity to decrease to half of its initial value is known as the half-life.

Given:

N0 = is the initial amount of cesium-137 = 8.0 Kg

N = is the amount remaining after a time =  Unknown

t =  Duration of cesium-137 decay in 8.0 Kg = 60 years

t1/2 = half-life of cesium-137 = 30.0 years

Formula = N/No = (1/2)^t/t1/2

After putting the value:

N/8= (1/2)^60/30

N/8= (1/2)^2

N/8= 1/4

4N= 8

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N= 2 Kg

As a result, 2 Kg of cesium-137 will be present after 60 years.

Learn more about the half-life here,

brainly.com/question/14018709

#SPJ4

8 0
2 years ago
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