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alexira [117]
3 years ago
7

An element has three stable isotopes with masses of 27.977 amu, 28.976 amu, and 29.973 amu. The heavier two isotopes have an abu

ndance of 4.68% and 3.09%, respectively. What is the mass of the element?A) 29.251
B) 27.684
C) 28.085
D) 28.991
E) 30.107
Chemistry
1 answer:
krok68 [10]3 years ago
5 0

Answer:

The mass of the element is 28.085 amu

Explanation:

Step 1: Data given

Masses of isotopes:

27.977 amu ⇒

28.976 amu ⇒ 4.68%

29.973 amu ⇒  3.09%

Step 2: Calculate the abundance of the other isotope

100% - 4.68% - 3.09 % = 92.23 %

Step 3: calculate the mass othe element

0.9223 * 27.977 + 0.0468 * 28.976 + 0.0309*29.973 = total mass of the element

Total mass of the element = 28.085 amuj

The mass of the element is 28.085 amu

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A student wants to make a 0.600 M aqueous solution of barium sulfate, BaSO4, and has a bottle containing 12.00 g of barium sulfa
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<u>Answer: </u>The volume of the solution is 85.7 mL

<u>Explanation:</u>

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

\text{Molarity of solution}=\frac{\text{Given mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (mL)}} .....(1)

We are given:

Molarity of solution = 0.600 M

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Putting values in equation 1, we get:

0.600=\frac{12.00\times 1000}{233.4\times \text{Volume of solution}}\\\\\text{Volume of solution}=\frac{12.00\times 1000}{233.4\times 0.600}=85.68mL=85.7mL

The rule of significant number that is applied for the problems having multiplication and division:

The least number of significant figures in any number of the problem determines the number of significant figures in the answer.

Here, the least number of significant figures is 3 that is determined by the number, 0.600. Thus, the answer must have these many significant figures only.

Hence, the volume of the solution is 85.7 mL

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