Answer:
![p[H+] = 10.042](https://tex.z-dn.net/?f=p%5BH%2B%5D%20%3D%2010.042)
Explanation:
As we know that
......eq (1)
we will calculate the pH of OH- and then we will calculate the pH of H+
So p[OH-] ![= - log [1.10 * 10^{-4}]](https://tex.z-dn.net/?f=%3D%20-%20log%20%5B1.10%20%2A%2010%5E%7B-4%7D%5D)
Solving the right side of the equation, we get
p[OH-]
![= - [-3.958]\\= 3.958](https://tex.z-dn.net/?f=%3D%20-%20%5B-3.958%5D%5C%5C%3D%203.958)
Now we know that

Substituting the value of pOH in the above equation, we get -
![14.0 = p[H+] + 3.958\\p[H+] = 14 - 3.958\\p[H+] = 10.042](https://tex.z-dn.net/?f=14.0%20%3D%20p%5BH%2B%5D%20%2B%203.958%5C%5Cp%5BH%2B%5D%20%3D%2014%20-%203.958%5C%5Cp%5BH%2B%5D%20%3D%2010.042)
Answer:
A penny dissolves in hydrochloric acid if the copper coating is filed down in several spot... ... When The Zinc In A Certain Penny Dissolves, The Total Volume Of Gas ... is filed down in several spots (so that the hydrochloric acid can reach the zinc). The reaction between the acid and the zinc 2H+(aq)+Zn(s)→H2(g)+Zn2+(aq) .
Answer:
Explanation:
C decays by a process called beta decay. During this process, an atom of 14C decays into an atom of 14N, during which one of the neutrons in the carbon atom becomes a proton. This increases the number of protons in the atom by one, creating a nitrogen atom rather than a carbon atom.
Answer:
Concentration of unknown solution is 0.0416 M
Explanation:
As we know
Absorbance is equal to the product of molar absorptivity of KMnO4 m, path length and concentration
From the given set of graphical data, it is clear that the absorbance vs concentration is a straight line.
From the graph, we can obtain-
Y = 5.73 X – 0.0065
Absorbance = 0.232
0.232 = 5.73 X – 0.0065
X = 0.0416
Concentration of unknown solution is 0.0416 M
Answer:
pH 
Explanation:
For every mole of hydrochloric acid, one mole of hydronium ion is required. Thus, in order to neutralize 0.014 moles of HCL, 0.014 moles of hydronium is required.
![[H_3O^+] = [HCl] = 0.014](https://tex.z-dn.net/?f=%5BH_3O%5E%2B%5D%20%3D%20%5BHCl%5D%20%3D%200.014)
pH ![= -log [H^+] = -log [H_3O^+]](https://tex.z-dn.net/?f=%3D%20-log%20%5BH%5E%2B%5D%20%3D%20-log%20%5BH_3O%5E%2B%5D)
Substituting the available values in above equation, we can say that the pH of the solution is equal to

pH 
pH of a
M HCL solution 