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icang [17]
1 year ago
7

Find the equation of the linear function represented by the table below in slope-intercept form.Answer: ?(Important: Please chec

k the attached photo before answering the question)

Mathematics
1 answer:
Salsk061 [2.6K]1 year ago
5 0

The Slope-Intercept form of the equation of the line is:

y=mx+b

Where "m" is the slope of the line and "b" is the y-intercept.

The slope can be found with:

m=\frac{y_2-y_1}{x_2-x_1}

Choose two points from the table. These could be the points (1,-4) and (4,-19). You can set up that:

\begin{gathered} y_2=-19 \\ y_1=-4 \\ x_2=4 \\ x_1=1 \end{gathered}

Substituting values, you get that the slope of this line is:

m=\frac{-19-(-4)}{4-1}=-5

You can substitute the slope and the first point into the equation in Slope-Intercept form:

-4=1(-5)+b

Solve for "b":

\begin{gathered} -4+5=b \\ b=1 \end{gathered}

Therefore, the Equation of this line in Slope-Intercept form is:

y=-5x+1

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Find the endpoint of the line segment with the given endpoint and midpoint.
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Answer:

(10, 2)

Step-by-step explanation:

To get from the given endpoint to the midpoint, 6 was added to x and 2 was added to y. As per the definition of a midpoint, the resulting two line segments will be congruent (first endpoint and midpoint congruent to midpoint and second endpoint). Use the same formula (x + 6, y + 2) to find the second endpoint (use the x and y of the midpoint):

(x + 6, y + 2)

(4 + 6, 0 +2)

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8 0
3 years ago
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What is the measure of EG?
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The first thing you should know in this case is that a circumference has a total measure in 360 degrees.
 We have then that the formula to find EG in this case is:
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 We substitute the values:
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 Answer
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3 years ago
The amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.2 minutes and
Ksju [112]

Answer:

A) 1

B) 1

C) 0

Step-by-step explanation:

The amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.2 minutes and standard deviation 1.5 minutes. Suppose that a random sample of n = 49 customers is observed. Find the probability that the average time waiting in line for these customers is A) Less than 10 minutes B) Between 5 and 10 minutes C) Less than 6 minutes

We solve this question using the z score formula

z = (x-μ)/σ/√n, where

x is the raw score

μ is the population mean

σ is the population standard deviation.

n = number of random samples

A) Less than 10 minutes

x < 10

z = 10 - 8.2/ 1.5 / √49

z = 8.4

P-value from Z-Table:

P(x<10) = 1

B) Between 5 and 10 minutes

For x = 5 minutes

z = 5 - 8.2/ 1.5 / √49

z = -14.93333

P-value from Z-Table:

P(x = 5) = 0

For x = 10 minutes

z = 10 - 8.2/ 1.5 / √49

z = 8.4

P-value from Z-Table:

P(x = 10) = 1

The probability that the average time waiting in line for these customers is between 5 and 10 minutes

P(x = 10) - P(x = 5)

= 1 - 0

= 1

C) Less than 6 minutes

x < 6

z = 6 - 8.2/ 1.5 / √49

z = -10.26667

P-value from Z-Table:

P(x<6) = 0

6 0
3 years ago
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If a student runs 4K in 1/2 hours, then he would run 8k In 1 hour, so, 8km/h
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The perimeter of a square is 80-64y units. Which expression can be used to show the side length of one side of the square?
nalin [4]
I think it’s 20-16y :)
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