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Answer: option D. the ability of a base to react with a soluble metal salt.
Justification:
NaOH is a strong base, which means that in water it will dissociate according to this reaction:
- NaOH(aq) → Na⁺ (aq) + OH⁻ (aq)
On the other hand, CuSO₄ is a soluble ionic salt which in water will dissociate into its ions according to this other reaction:
Hence, in solution, the sodium ion (Na⁺) will react with the metal salt in a double replacement reaction, where the highly reactive sodium ion (Na⁺) will substitute the Cu²⁺ in the CuSO₄ to form the sodium sulfate salt, Na₂SO₄ (water soluble), and the copper(II) hydroxide, Cu(OH)₂ (insoluble).
That is what the given reaction represents:
CuSO₄ (aq) + 2NaOH(aq) → Cu(OH)₂(s) + Na₂SO₄(aq)
↑ ↑ ↑ ↑
soluble metal salt strong base insoluble base solube salt
Explanation:
A precipitate is defined as an insoluble substance that emerges upon mixing of two aqueous solutions.
For example,
As precipitate is a solid and it is represented by (s). And, an aqueous solution is represented by (aq).
So, the products of the given reactants will be as follows.
Hence, we can conclude that out of the given options, these two equations will produce a precipitate.
The answer is A this is a conclusion.
Answer:
Check explanation.
Explanation:
Electron affinity simply means the ability of an atom to gain an electron. Electron affinity can also be defined as the change in energy of a neutral atom in the gaseous phase when an electron is added to the atom to form a negative ion.
Electron affinity characteristics trends is that it increases upward for the groups and from left to right across periods of a periodic chart.
Both Bromine and Iodine are both found in group 7/17 , that is the Halogens on the periodic chart. Group seven element has 7 valence electrons(that is, it remains 1 electron for them to reach their octet). Hence, when an electron is added to these Halogens, energy will be released.
WHAT CAUSES THE DIFFERENCES in ELECTRON AFFINITY for bromine and IODINE are;
(1). Atomic size: iodine atom is larger than a bromine atom. Therefore, outermost electrons of Iodine are located further away from the nucleus.
(2). The shielding effect: Iodine has an extra full shell of core electrons between the nucleus and the outermost shell and these extra core electrons will shield the outermost electrons from the nucleus.
So, less energy will be released when one mole of electrons is added to one mole of Iodine atoms as compare with Bromine atoms