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Ghella [55]
3 years ago
12

Which is the anode (oxidation) and cathode (reduction)?

Chemistry
1 answer:
arsen [322]3 years ago
8 0

Answer:

2H+ + 2e - ---> H2(g) is the cathode

2Cl - ---> Cl2(g) + 2e - is the anode

Explanation:

Hydrogen ion has gained two electrons, making it undergo reduction. While chlorine has lose two electrons, hence undergoing oxidation.

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The compound magnesium iodide is a strong electrolyte write the reaction when solid magnesium iodide is put into water
mestny [16]
  The  reaction  for magnesium  iodide  when put into water  is  as below

 MgI2(s) →  Mg^2+(aq)   + 2I^-(aq)

when  magnesium iodide  but into water it dissociate/ ionize  completely  into  Mg^2+  and  2l^-   ions. Magnesium iodide dissociate/ionize  completely because  magnesium  iodide  is a strong electrolyte  which  dissociate/ ionize  completely into their ions  when it is put into   water .
7 0
3 years ago
Measure of the average kinetic energy of molecules in an in an object
algol13
Yes because molecules is solid
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Scientific process how can a casual question be answered 3 hypotheses water experiment
Vlad1618 [11]

There are 3 experiments which helps to under water evaporation system.

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brainly.com/question/24258

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3 0
2 years ago
Find the mass in grams of 3.00 x 1023 molecules of F2
LUCKY_DIMON [66]
<h3>Answer:</h3>

18.9 g F₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.00 × 10²³ molecules F₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of F₂ (Diatomic) - 38.00 g/mol

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 3.00 \cdot 10^{23} \ molecules \ F_2(\frac{1 \ mol \ F_2}{6.022 \cdot 10^{23} \ molecules \ F_2})(\frac{38.00 \ g \ F_2}{1 \ mol F_2})
  2. Multiply:                                                                                                             \displaystyle 18.9306 \ g \ F_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

18.9306 g F₂ ≈ 18.9 g F₂

8 0
3 years ago
30) When ionic bonds are formed, metallic atoms tend to
Strike441 [17]

Answer:

B is the answer

Explanation:

7 0
3 years ago
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