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3 years ago

6x – 4 < –34 or 3x + 10 > 10

2 answers:

5 0

1. 6x-4< -34, or 3x+10 > 10.

6x-4 < -34. 
6x < -34 + 4 
6x < -30 
X < -5. 

3x + 10 > 10. 
3x > 10 - 10 
3x > 0 
X > 0. 

2. -2 <= 2x-4 < 4. 
Add 4 to each end and the center: 
-2 + 4<= 2x-4+4 < 4+4. 
2 <= 2x < 8 
Divide each end and center by 2: 
1 <= X < 4. 

The compound inequality is actually 2 
inequalities and can be solved separately: 

2x-4 => -2, and 2x-4 < 4. 

2x-4 => -2. 
2x => -2+4 
2x=> 2 
X => 1. 

2x-4 < 4. 
2x < 4+4 
2x < 8 
X < 4. 

Solution: 1< = X < 4. or X => 1, and X<4 

 TO CHECK: 

1. Substitute any number < -5 for X. 
Eq2: Subst. any number > 0 for X.

kvv77 [185]3 years ago

5 0

Left side: x < -5

Right side: x > 0

Not sure if you want to graph it on a number line or a coordinate plane

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A friend calls you and asks you to meet at the park 2 mi away in 25 min. You set off on your skateboard after the call. At what

xeze [42]

Answer:

speed greater than 0.08 mi/min

Step-by-step explanation:

given data

distance = 2 mi

time = 25 min

to find out

the distance you travel and your speed and time related

solution

we know that distance is

distance = speed × time ...............1

so at park at most 25 min

so we need time = $\frac{distanec}{speed} \leq 25$

so here

we know

$\frac{2}{25} \leq speed$

$0.08 \leq speed$

so we can say that he need to run at speed greater than 0.08 mi/min

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3 years ago

Find the surface area of this rectangular prism . thanks!!!!!!!

agasfer [191]

Answer

Step-by-step explanation:

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2 years ago

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WARRIOR [948]

02 did u know
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3 years ago

Can you help me with this problem please

Over [174]

Remark

I think you want us to do both 3 and 4

Three

QR is 4 points going left from the y axis + 2 points going right from the y axis.

QR = 6 units long.

RT is 4 units above the x axis and 3 units below the x axis

RT = 7 units long

TS = 3 units. For this one you just go from T to S. The graph really helps you. You just need to count.

Problem 4

You need to find the area of the combined figure. You could do it as a trapezoid, which might be the easiest way. I'll do that first.

Area = (b1 + b2)*h/2

Givens

B1 = QR = 6

B2 = UT + TS = 6 + 3 = 9

h = RT = 7

Area

Area = (6 + 9)*7/2

Area = 15 * 7 / 2

Area = 52.5

Comment

You could break this up into a rectangle + a triangle

Find the area of QRTU and add the Area of triangle RTS

Area of the rectangle = L * W

L = RT = 7

W = QR = 6

Area = 7 *6 = 42

Area of the triangle = 1/2 * B * H

B = TS = 3

H = RT =7

Area = 1/2 * 3 * 7

Area = 1/2 * 21

Area = 10.5

Total Area = 42 + 10.5 = 52.5 Both answers agree.

3 0

3 years ago

the first group of students consists of 10 and their average age was 13 years old the next group consisted of 30 students and th

Kazeer [188]

Answer: The average was 9 years old find the average age of both groups is 10 years old.

Step-by-step explanation:

Formula foe average : $\text{Average} =\dfrac{\text{Sum of all observations}}{\text{Number of observations}}$

Given : The first group of students consists of 10 and their average age was 13 years old.

i.e. $13=\dfrac{\text{Sum of ages of students of first group}}{10}\\\\\Rightarrow\ \text{Sum of ages of students of first group}=13\times10=130$ (1)

The next group consisted of 30 students and their average was 9 years old.

i.e. $9=\dfrac{\text{Sum of ages of students of next group}}{30}\\\\\Rightarrow\ \text{Sum of ages of students of nextgroup}=9\times30=270$ (2)

Then from (1) and (2) , the sum of both groups (first group and next group )students = 130+270 =400

Combined students of both groups (first and next group )= 10+30=40

Now , the average of both groups = $\dfrac{\text{Sum of combined students}}{\text{combined students}}$

$=\dfrac{400}{40}=10$

Hence, the average was 9 years old find the average age of both groups is 10 years old.

4 0

3 years ago