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n200080 [17]
1 year ago
6

Now examine salts containing the halide anions, cl- and br-. Most of these are soluble. What two cations listed lead to insolubl

e halide salts?.
Chemistry
1 answer:
tatiyna1 year ago
8 0

Ag+ and Pb+2 are two cations that are suggested as producing insoluble halide salts when studying salts containing the halide anions, cl- and br-. First, the charge's number is provided.

Neutral binary salts, also referred to as halide salts, are mixtures of metals and non-metals. The non-metal behaves in a reduced oxidation state at all times. They are the outcome of mixing a hydroxide and hydracid. halide salts of haloids are produced by the reaction of a hydroxide and a hydracid.

Ions are cations with positive charges. They emerge when the electrons of an elemental metal are lost. However, they don't lose any protons; they only lose one or more electrons. To denote a cation, the charge is superscripted following the element name or chemical formula.

Learn more about halide salts here

brainly.com/question/20815131

#SPJ4

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The combustion of 3.795 mg of liquid B, which contains only C, H, and O, with excess oxygen gave 9.708 mg of CO2 and 3.969 mg of
attashe74 [19]

Answer:

Explanation:

9.708 mg of CO₂ will contain 12 x 9.708 / 44 = 2.64 g of C .

3.969 mg of H₂O will contain 2 x 3.969 / 18 = .441 g of H .

mg of O in given liquid B = 3.795 - ( 2.64 + .441 ) = .714 mg

ratio of mg of C , H , O in the compound = 2.64 : .441 : .714

ratio of no of atoms  of C , H , O in the compound

= 2.64 / 12 : .441 /1 : .714 / 16

= .22 : .44 : .0446

= .22 / .22 : .44 / .22 : .044 / .22

= 1 : 2 : .2

1 x 5 : 2 x 5 : .2 x 5

= 5 : 10 : 1

empirical formula of the compound = C₅H₁₀O

Volume of 89.8 mL at 1 .00 atm at 200⁰C

volume of gas at 1 atm and 0⁰C = 89.8 x 273 / 473 mL

= 51.83 mL

51.83 mL weighs .205 g

22400 mL will weigh .205 x 22400 / 51.83 g

= 88.6 g

So molecular weight = 88.6

Let molecular formula be (C₅H₁₀O)ₙ

molecular weight = n ( 5 x 12 + 10 + 16 )

= 86 n

86 n = 88.6

n = 1 approx

So molecular formula is same as empirical formula

C₅H₁₀O is molecular formula .

6 0
3 years ago
In chemical kinetics, the magnitude of the rate constant depends on: I. the reaction time of the chemical reaction II. the activ
Snowcat [4.5K]

Answer:

THE TEMPERATURE AT WHICH THE CHEMICAL REACTION IS BEING CONDUCTED.

Explanation:

The reaction rate constant is dependence on the temperature in which the reaction takes place. The rate of a reaction and the activation energy relationship is given by the Arrhenius equation with the rate constant as a function of temperature.

Mathematically, the rate constant is expressed as;

k(T) = Ae^-Ea/RT

where Ea is the activation energy, R is the gas constant, Ae is the pre-exponential factor and it is the frequency at which a reactant molecule collide with each other, T is the temperature.

3 0
3 years ago
Power gathered from the sun and wind
Mademuasel [1]

Answer: B. Can provide humans with energy forever

Explanation:  The warm air rises and cooler air rushes in to take its place. The moving air is wind. As long as the sun shines, there will be winds on the Earth. We will never run out of wind energy.

7 0
3 years ago
Read 2 more answers
PLS HELP QUICK ALOTTT OF POINTS
timofeeve [1]

Answer:

\boxed {\boxed {\sf 0.80 \ mol\ F}}

Explanation:

We are asked to find how many moles are in 4.8 × 10²³ fluorine atoms. We convert atoms to moles using Avogadro's Number or 6.022 × 10²³. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance. In this case, the particles are atoms of fluorine.

We will convert using dimensional analysis and set up a ratio using Avogadro's Number.

\frac {6.022 \times 10^{23} \ atoms \ F}{ 1 \ mol \ F}

We are converting 4.8 × 10²³ fluorine atoms to moles, so we multiply the ratio by this number.

4.8 \times 10^{23} \ atoms \ F *\frac {6.022 \times 10^{23} \ atoms \ F}{ 1 \ mol \ F}

Flip the ratio so the units of atoms of fluorine cancel each other out.

4.8 \times 10^{23} \ atoms \ F *\frac { 1 \ mol \ F}{6.022 \times 10^{23} \ atoms \ F}

4.8 \times 10^{23}  *\frac { 1 \ mol \ F}{6.022 \times 10^{23} }

Condense into 1 fraction.

\frac { 4.8 \times 10^{23} }{6.022 \times 10^{23} } \ mol \ F

Divide.

0.7970773829 \ mol \ F

The original measurement of atoms has 2 significant figures, so our answer must have the same. For the number we found, that is the hundredths place. The 7 in the thousandths tells us to round the 9 in the hundredths place up to a 0. Then, we also have to round the 7 in the tenths place up to an 8.

0.80 \ mol \ F

4.8 × 10²³ fluorine atoms are equal to <u>0.80 moles of fluorine.</u>

6 0
3 years ago
What are the controlled variables for water of crystallization experiment?
yarga [219]

Given what we know, we can confirm that as with any experiment, the control variable will be the one that through each trial of the experiment, no matter how many times it is performed, stays constant.

<h3>What is a controlled variable?</h3>
  • A variable that remains constant through an experiment.
  • They are used to compare results to the normal condition.
  • They are also used to isolate the changes to one factor at a time and thus know its exact effects on the outcome.
  • This increases the accuracy of the data and the subsequent conclusion.

Therefore, we can confirm that if a variable stays constant through each phase and trial of an experiment, it is considered to be a controlled variable and is useful in order to increase the accuracy of the conclusion.

To learn more about control variables visit:

brainly.com/question/17555102?referrer=searchResults

7 0
3 years ago
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