All categories

3 years ago

Which of the following occupies a volume? solids liquids gases all of the above

Chemistry

2 answers:

sasho [114]3 years ago

5 0

<u>Answer:</u> The correct answer is all of the above.

<u>Explanation:</u>

Volume is defined as the amount of space that a substance is occupying. The S.I. unit of this property is Liter (L).

There are 3 states of matter:

Solid state: In this state, the particles of the state are orderly arranged and it occupies specific shape and volume.
Liquid state: In this state, the particles of the state are not orderly arranged and it occupies the shape and volume of the container.
Gaseous state: In this state, the particles are randomly arranged and the particles occupies the shape and volume of the container in which it is kept.

Hence, the volume is occupied by all the three states.

Thus, the correct answer is all of the above.

yanalaym [24]3 years ago

4 0

Solids, liquids and gases all take up volume.

You might be interested in

While a certain isotope decays, it emits photons. What kind of decay is happening?

gizmo_the_mogwai [7]

The correct answer is Gamma decay. It happens after beta and alpha decay because what's left after those two can enter a new process of gamma decay. This releases gamma rays which is a more complex term for the photons that you mentioned before. These rays can be dangerous for humans so care not to get caught in them.

6 0

2 years ago

Read 2 more answers

Use bond energies to calculate the enthalpy of reaction for the combustion of ethane. Average bond energies in kJ/mol C-C 347, C

ivanzaharov [21]

The enthalpy of reaction for the combustion of ethane 2CH₃CH₃ + 7O₂ → 4CO₂ + 6H₂O calculated from the average bond energies of the compounds is -2860 kJ/mol.

The reaction is:

2CH₃CH₃ + 7O₂ → 4CO₂ + 6H₂O (1)

The enthalpy of reaction (1) is given by:

$\Delta H = \Delta H_{r} - \Delta H_{p}$ (2)

Where:

r: is for reactants

p: is for products

The bonds of the compounds of reaction (1) are:

2CH₃CH₃: 2 moles of 6 C-H bonds + 2 moles of 1 C-C bond

7O₂: 7 moles of 1 O=O bond

4CO₂: 4 moles of 2 C=O bonds

6H₂O: 6 moles of 2 H-O bonds

Hence, the enthalpy of reaction (1) is (eq 2):

$\Delta H = \Delta H_{r} - \Delta H_{p}$

$\Delta H = 2*\Delta H_{CH_{3}CH_{3}} + 7\Delta H_{O_{2}} - (4*\Delta H_{CO_{2}} + 6*\Delta H_{H_{2}O})$

$\Delta H = 2*(6*\Delta H_{C-H} + \Delta H_{C-C}) + 7\Delta H_{O=O} - (4*2*\Delta H_{C=O} + 6*2*\Delta H_{H-O})$

$\Delta H = [2*(6*413 + 347) + 7*498 - (4*2*799 + 6*2*467)] kJ/mol$

$\Delta H = -2860 kJ/mol$

Therefore, the enthalpy of reaction for the combustion of ethane is -2860 kJ/mol.

I hope it helps you!

7 0

2 years ago

202H8(9) + 7 O2(g) > 4CO2(g) + 6 H2O(9).

lilavasa [31]

since the concentration of Carbon Dioxide will increase, it would make Q > K, cause equilibrium to shift in the direction with less moles of gas to alleviate the extra pressure. In this case, the reaction will shift left because there are fewer moles of gas present.

4 0

2 years ago

The

Marat540 [252]

Answer:

Isotopes

Explanation:

Isotopes are atoms of the same element that contain an identical number of protons, but a different number of neutrons. Despite having different numbers of neutrons, isotopes of the same element have very similar physical properties.

4 0

3 years ago

Pls help i will mark brainlist

Veseljchak [2.6K]

58.5 moles

can i plz get brainliest

4 0

2 years ago