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3 years ago

Which of the following occupies a volume? solids liquids gases all of the above

Chemistry

2 answers:

sasho [114]3 years ago

5 0

<u>Answer:</u> The correct answer is all of the above.

<u>Explanation:</u>

Volume is defined as the amount of space that a substance is occupying. The S.I. unit of this property is Liter (L).

There are 3 states of matter:

Solid state: In this state, the particles of the state are orderly arranged and it occupies specific shape and volume.
Liquid state: In this state, the particles of the state are not orderly arranged and it occupies the shape and volume of the container.
Gaseous state: In this state, the particles are randomly arranged and the particles occupies the shape and volume of the container in which it is kept.

Hence, the volume is occupied by all the three states.

Thus, the correct answer is all of the above.

yanalaym [24]3 years ago

4 0

Solids, liquids and gases all take up volume.

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an atom contains 32 protons and has a mass number of approximately 72 amu what is the chemical symbol for the atom

olga nikolaevna [1]

I belive it would be Hf (hafanium).

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3 years ago

Read 2 more answers

What is the percent composition of N H S O in (NH4)2SO4

Lena [83]

Answer:

The percent composition is 21% N, 6% H, 24% S and 49% O.

Explanation:

1st) The molar mass of (NH4)2SO4 is 132g/mol, and it represents the 100% of the mass composition.

In 1 mole of (NH4)2SO4, there are:

- 2 moles of N.

- 8 moles of H.

- 1 mole of S.

- 4 moles of O.

2nd) It is necessary to calculate the mass of each element, multiplying its molar mass by the number of moles:

- 2 moles of N (14g/mol) = 28g

- 8 moles of H (1g/mol) = 8g

- 1 mole of S (32g/mol) = 32g

- 4 moles of O (16g/mol) = 64g

3rd) With a mathematical rule of three we can calculate the percent composition of each element in the molecule of (NH4)2SO4:

$\begin{gathered} \text{ Nitrogen:} \\ 132g-100\% \\ 28g-x=\frac{28g*100\%}{132g} \\ x=21\% \end{gathered}$ $\begin{gathered} \text{ Hydrogen:} \\ 132g-100\operatorname{\%} \\ 8g-x=\frac{8g*100\operatorname{\%}}{132g} \\ x=6\% \end{gathered}$ $\begin{gathered} \text{ Sulfur:} \\ 132g-100\operatorname{\%} \\ 32g-x=\frac{32g*100\operatorname{\%}}{132g} \\ x=24\% \end{gathered}$ $\begin{gathered} \text{ Oxygen:} \\ 100\%-21\%-6\%-24\%=49\% \\ \\ \end{gathered}$

In this case, we can calculate the percent composition of Oxygen by subtracting the other percentages, since the total must be 100%.

So, the percent composition is 21% N, 6% H, 24% S and 49% O.

8 0

1 year ago

You dissolve 14 g of Mg(NO3)2 in water and dilute to

mart [117]

Answer:

0.127M

Explanation:

Molarity of a solution = number of moles (n) ÷ volume (V)

Molar mass of Mg(NO3)2 = 24 + (14 + 16(3)}2

= 24 + {14 + 48}2

= 24 + 124

= 148g/mol

Using the formula, mole = mass/molar mass, to convert mass of Mg(NO3)2 to mole

mole = 14g ÷ 148g/mol

mole = 0.095mol

Volume = 750mL = 750/1000 = 0.75L

Molarity = 0.095mol ÷ 0.75L

Molarity = 0.127M

3 0

3 years ago

1 3.1.2

Pachacha [2.7K]

Answer: (Kr) 5s2

Explanation:

Apex

7 0

3 years ago

A water sample has a pH of 8.2 and a bicarbonate concentration of 97 mg/L. What is the alkalinity of the sample in moles/L and i

goldfiish [28.3K]

Answer:6.94

Explanation:

Molar mass of CaCO3=40+12+16×3

=40+12+48=100g/mol

Moles=mass of substance/molar mass

=97mg/100g=0.097/100=0.00097moles/L.

PH=-log[CaCo3]=-log(0.00097)=6.94

P.s it's log to base e

3 0

3 years ago