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3 years ago

6

Given 7.40 g of butanoic acid and excess ethanol, how many grams of ethyl butyrate would be synthesized, assuming a complete 100

% yield?

1 answer:

Dafna11 [192]3 years ago

4 0

On complete conversion (100% yield) 9.75 g of ethyl butyrate will be produced. Below is the solution.....

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Partner Namets) For each of the following reactions carried out: Write the balanced chemical equation, the full ionic equation,

torisob [31]

Answer : The full balanced ionic equation will be,

$2KI(aq)+Pb(NO_3)_2(aq)\rightarrow 2KNO_3(aq)+PbI_2(s)$

Reactants are lead nitrate and potassium iodide.

Products are lead iodide and potassium nitrate.

The spectator ions are, $K^+,NO_3^-$

Explanation :

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

When potassium iodide react with lead nitrate then it gives potassium nitrate and lead iodide as a product.

The full balanced ionic equation will be,

$2KI(aq)+Pb(NO_3)_2(aq)\rightarrow 2KNO_3(aq)+PbI_2(s)$

The ionic equation in separated aqueous solution will be,

$2K^+(aq)+2I^{-}(aq)+Pb^{2+}(aq)+2NO_3^{-}(aq)\rightarrow PbI_2(s)+2K^+(aq)+2NO_3^{-}(aq)$

In this equation, $K^+\text{ and }NO_3^-$ are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

$Pb^{2+}(aq)+2I^{-}(aq)\rightarrow PbI_2(s)$

4 0

4 years ago

What's the empirical and molecular weight of C14H22N4O8? What's the molecular formula of C14H22N4O8?

Inessa05 [86]

374u

187u

C₁₄H₂₂N₄O₈

Explanation:

To find the molecular weight of the compound C₁₄H₂₂N₄O₈ we simply sum that atomic masses of the given elements in the compound.

The empirical weight is determined by using the simplest ratio of the elements involved in the compound;

Molecular weight of C₁₄H₂₂N₄O₈;

atomic mass of C = 12g/mol

H = 1g/mol

N = 14g/mol

O = 16g/mol

Molecular weight = 14(12) + 22(1) + 4(14) + 8(16)

= 168 + 22 + 56 + 128

= 374u

Empirical weight:

Empirical formula:

C₁₄ H₂₂ N₄ O₈

14 : 22 : 4 : 8

divide by 2:

7 : 11 : 2 : 4

empirical formula C₇H₁₁N₂O₄

empirical weight = $\frac{molecular weight}{2}$ = $\frac{374}{2}$ = 187u

The molecular formula is the actual combination of atoms in a compound. so the molecular formula of the compound is C₁₄H₂₂N₄O₈

learn more:

Molecular mass brainly.com/question/5546238

#learnwithBrainly

8 0

3 years ago

In which cell organelle does protein synthesis occur? cytoplasm mitochondria ribosome cell membrane

MariettaO [177]

It occurs in The ribosome

8 0

3 years ago

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Pure titanium metal is produced by reaction titanium(IV) chloride with magnesium metal. The equation for the reaction is: TiCl4(

qaws [65]

Answer:

The answer to your question is 1.013 Kg

Explanation:

TiCl₄ + 2Mg ⇒ 2MgCl₂ + Ti

mass of Mg = ?

mass of Ti = 1 kg

Process

1.- Calculate the molar mass of Magnesium and titanium (IV)

Mg = 24.3 g x 2 = 48.6 g

Ti = 48 g

2.- Write a proportion (rule of three)

48.6 g of Mg ------------- 48 g of Ti

x ------------- 1000 g of Ti

x = (1000 x 48.6) / 48

3.- Result

mass of Magnesium = 1012.5g

= 1.013 kg

7 0

3 years ago

True or false there are equal numbers of protons and electrons in neutral atoms.

Akimi4 [234]

true the answer is true

5 0

3 years ago

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