Ask question

Ask question

All categories

3 years ago

6

Given 7.40 g of butanoic acid and excess ethanol, how many grams of ethyl butyrate would be synthesized, assuming a complete 100

% yield?

1 answer:

Dafna11 [192]3 years ago

4 0

On complete conversion (100% yield) 9.75 g of ethyl butyrate will be produced. Below is the solution.....

You might be interested in

Suppose 215 g of NO3- flows into a swamp each day. What volume of CO2 would be produced each day at 17.0°C and 1.00 atm?

charle [14.2K]

Answer:

The answer is " $41.23 \ L\ N_2$ "

Explanation:

$2 NO_3^{-} + 10 e^{-} + 12 H^{+} \longrightarrow N_2 + 6 H_2O\\\\= \frac{( 215 \ g \ NO_3^{-})}{(62.0049 \frac{\ g NO_3^{-}}{mol})} \times \frac{(1 \ mol \ N_2}{ 2 \ mol \ NO_3^{-})}\\\\$

$=3.46746789 \times 0.5\\\\= 1.733 \ mol \ N_2 \\\\\to V = \frac{nRT}{P} \\\\= (1.733 \ mol) \times (0.08205746 \frac{L\ atm}{Kmol}) \times \frac{ (17 + 273) K}{(1.00 atm)}\\\\= 41.23$

8 0

2 years ago

If a plant has a total of 17g of carbon dioxide and water reacting in photosynthesis, then how much glucose and oxygen will the

love history [14]

Answer:

Basically it would be 8.5g. Not total sure.

Explanation:

If its right plz give brainlest.

6 0

3 years ago

Read 2 more answers

Calculate the pressure of 2.50 Liters of a gas at 25.0oC if it has a volume of 4.50 Liters at

MariettaO [177]

Answer:

P_2 =0.51 atm

Explanation:

Given that:

Volume (V1) = 2.50 L

Temperature (T1) = 298 K

Volume (V2) = 4.50 L

at standard temperature and pressure;

Pressure (P1) = 1 atm

Temperature (T2) = 273 K

Pressure P2 = ??

Using combined gas law:

$\dfrac{P_1V_1}{T_1} = \dfrac{P_2V_2}{T_2} \\ \\ \dfrac{1 *2.5}{298} = \dfrac{P_2*4.5}{273}$

$0.008389261745 \times 273 = 4.5P_2$

$P_2 =\dfrac{0.008389261745 \times 273 }{4.5}$

$P_2 =0.51 \ atm$

4 0

2 years ago

Which unit can be used to express the rate of a reaction?

Ugo [173]

<span>A) mL / s

This is the amount of milliliters per second</span>

4 0

2 years ago

Read 2 more answers

What is the total number of protons, neutrons, and electrons in a thallium, TI, atom that has a mass number of 204

a_sh-v [17]

Answer:

Name, Thallium. Symbol, Tl. Atomic Number, 81. Atomic Mass, 204.3833 atomic mass units. Number of Protons, 81. Number of Neutrons, 123. Number of Electrons, 81 ... It has a metallic luster when it is first exposed to air but it tarnish quickly

Explanation:

Hope this helped :)

6 0

3 years ago