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Mashutka [201]
2 years ago
6

A gas is collected at 25.0 °C and 755.0 mm Hg. When the temperature is

Chemistry
1 answer:
Mashcka [7]2 years ago
7 0

Answer:

691.7 mmHg is the resulting pressure

Explanation:

Tha Gay-Lussac's law states that the pressure of a gas is directly proportional to its absolute temperature under constant volume. The equation is:

P1T2 = P2T1

<em>Where P is pressure and T asbolute temperature of 1, initial state and 2, final state of the gas.</em>

<em />

Computing the values of the problem:

T1 = 273 + 25 = 298K

P1 = 755.0mmHg

T2 = 273 + 0 = 273K

P2 = ?

755.0mmHg*273K = P2*298K

<h3>691.7 mmHg is the resulting pressure</h3>
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Air containing 0.04% carbon dioxide is pumped into a room whose volume is 6000 ft3. The air is pumped in at a rate of 2000 ft3/m
koban [17]

Here is the full question:

Air containing 0.04% carbon dioxide is pumped into a room whose volume is 6000 ft3. The air is pumped in at a rate of 2000 ft3/min, and the circulated air is then pumped out at the same rate. If there is an initial concentration of 0.2% carbon dioxide, determine the subsequent amount in the room at any time.

What is the concentration at 10 minutes? (Round your answer to three decimal places.

Answer:

0.046 %

Explanation:

The rate-in;

R_{in} = \frac{0.04}{100}*2000

R_{in} = 0.8

The rate-out

R_{out} = \frac{A}{6000}*2000

R_{out} = \frac{A}{3}

We can say that:

\frac{dA}{dt}= 0.8-\frac{A}{3}

where;

A(0)= 0.2% × 6000

A(0)= 0.002 × 6000

A(0)= 12

\frac{dA}{dt} +\frac{A}{3} =0.8

Integration of the above linear equation =

e^{\int\limits \frac {1}{3}dt } = e^{\frac{1}{3}t

so we have:

e^{\frac{1}{3}t}\frac{dA}{dt}} +\frac{1}{3}e^{\frac{1}{3}t}A = 0.8e^{\frac{1}{3}t

\frac{d}{dt}[e^{\frac{1}{3}t}A] = 0.8e^{\frac{1}{3}t

Ae^{\frac{1}{3}t} =2.4e\frac{1}{3}t +C

∴ A(t) = 2.4 +Ce^{-\frac{1}{3}t

Since A(0) = 12

Then;

12 =2.4 + Ce^{-\frac{1}{3}}(0)

C= 12-2.4

C =9.6

Hence;

A(t) = 2.4 +9.6e^{-\frac{t}{3}}

A(0) = 2.4 +9.6e^{-\frac{10}{3}}

A(t) = 2.74

∴ the concentration at 10 minutes is ;

=  \frac{2.74}{6000}*100%

= 0.0456667 %

= 0.046% to three decimal places

7 0
3 years ago
A mixture of two miscible liquids with a widely different boiling point is distilled. The temperature of distilled liquid is obs
svetoff [14.1K]

Answer:

The difference in temperature is significant means that the lower-boiling liquid finishes distilling at a temperature that is too low for the higher-boiling liquid to be in vapor form yet.

Explanation:

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Answer:

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What would the empirical formula be for the molecular compound CoH904?
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2 years ago
SECTION A
Burka [1]

Answer:

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Explanation:

I tried!

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