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3 years ago

The natural source of acidity in rain water is _____.

Chemistry

2 answers:

julia-pushkina [17]3 years ago

4 0

Answer:

carbonic acid

Explanation:

Carbonic acid refers to the natural existent acid in our atmosphere which is produced when water reacts with water vapor and it makes rain naturally acid. As a result, rainwater is always acidic. On the other hand, acid rain occurs when precipitation contains a higher than normal acidity and a pH lower than 5.0.

Vikki [24]3 years ago

4 0

Answer:

Carbonic acid

Explanation:

Hello,

In this case, due to the increasing concentration of carbon dioxide in the atmosphere, when it rains, the following chemical reaction occurs between water and carbon dioxide:

$CO_2+H_2O\rightarrow H_2CO_3$

Whose product is known as carbonic acid and it is the natural source of acidity in acid rain.

Regards.

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An ionic bond is between what kind of charged particles?

Lisa [10]

Answer: An ionic bond is a type of chemical bond formed through an electrostatic attraction between two oppositely charged ions. Ionic bonds are formed between a cation, which is usually a metal, and an anion, which is usually a nonmetal. A covalent bond involves a pair of electrons being shared between atoms.

Explanation:

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3 years ago

For the process 2SO2(g) + O2(g) --> 2SO3(g),

CaHeK987 [17]

Answer:

–187.9 J/K

Explanation:

The equation that relates the three quantities is:

$\Delta G = \Delta H - T \Delta S$

where

$\Delta G$ is the Gibbs free energy

$\Delta H$ is the change in enthalpy of the reaction

T is the absolute temperature

$\Delta S$ is the change in entropy

In this reaction we have:

ΔS = –187.9 J/K

ΔH = –198.4 kJ = -198,400 J

T = 297.0 K

So the Gibbs free energy is

$\Delta G=-198,400-(297.0)(-187.9)=254.2 kJ$

However, here we are asked to say what is the entropy of the reaction, which is therefore

ΔS = –187.9 J/K

8 0

3 years ago

How many moles are in 1.51x10^26 atoms of xenon (Xe)? Please and thank you :)!!

RoseWind [281]

<h3>Answer:</h3>

251 mol Xe

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 1.51 × 10²⁶ atoms Xe

[Solve] moles Xe

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

[DA] Set up: $\displaystyle 1.51 \cdot 10^{26} \ atoms \ Xe(\frac{1 \ mol \ Xe}{6.022 \cdot 10^{23} \ atoms \ Xe})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 250.747 \ mol \ Xe$

<u>Step 4: Check</u>

<em>Follow sig fig rule and round. We are given 3 sig figs.</em>

250.747 mol Xe ≈ 251 mol Xe

3 0

3 years ago

PLZ HELP, GIVING BRAINLIEST!!

andrew-mc [135]

Answer:

Option B. Decreasing the temperature of the solvent

Explanation:

Solubility is mostly enhanced by increasing the temperature of the solvent or solution. This means that am increase in temperature will increase the solubility and decreasing the temperature will decrease the solubility.

5 0

3 years ago

Read 2 more answers

A pound of margarine costs $1.39. What is the cost of a kilogram of margarine

den301095 [7]

Answer:

3.064 $

Solution:

First of all we will find the number of pounds contained by one Kg. Therefore, it is found that,

1 Kilogram = 2.20462 Pounds

Hence, as given,

1 Pound of Margarine costs = 1.39 Dollars

So,

2.20462 Pounds Margarine will cost = X Dollars

Solving for X,

X = (2.20462 Pounds × 1.39 Dollars) ÷ 1 Pound

X = 3.064 Dollars

8 0

3 years ago