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3 years ago

The natural source of acidity in rain water is _____.

Chemistry

2 answers:

julia-pushkina [17]3 years ago

4 0

Answer:

carbonic acid

Explanation:

Carbonic acid refers to the natural existent acid in our atmosphere which is produced when water reacts with water vapor and it makes rain naturally acid. As a result, rainwater is always acidic. On the other hand, acid rain occurs when precipitation contains a higher than normal acidity and a pH lower than 5.0.

Vikki [24]3 years ago

4 0

Answer:

Carbonic acid

Explanation:

Hello,

In this case, due to the increasing concentration of carbon dioxide in the atmosphere, when it rains, the following chemical reaction occurs between water and carbon dioxide:

$CO_2+H_2O\rightarrow H_2CO_3$

Whose product is known as carbonic acid and it is the natural source of acidity in acid rain.

Regards.

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Answer:

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Explanation:

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3 years ago

How many liters of solvent are needed to make a 6.5M solution with 34 mol of solute?

Dominik [7]

Answer:

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Explanation:

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3 years ago

A pycnometer is a precisely weighted vessel that is used for highly accurate density determinations. Suppose that a pycnometer h

dexar [7]

Answer:

5.758 is the density of the metal ingot in grams per cubic centimeter.

Explanation:

1) Mass of pycnometer = M = 27.60 g

Mass of pycnometer with water ,m= 45.65 g

Density of water at 20 °C = d = $998.2 kg/m^3$

1 kg = 1000 g

$1 m^3=10^6 cm^3$

$998.2 kg/m^3=\frac{998.2 \times 1000 g}{10^6 cm^3}=0.9982 g/cm^3$

Mass of water ,m'= m - M = 45.65 g - 27.60 g =18.05 g

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$Density=\frac{Mass}{Volume}$

$V=\frac{m'}{d}=\frac{18.05 g}{0.9982 g/cm^3}=18.08 cm^3$

2) Mass of metal , water and pycnometer = 56.83 g

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Mass of water when metal and water are together ,m''= 56.83 g - M'- M

56.83 g - 9.5 g - 27.60 g = 19.7 g

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Density of metal = d'

Volume of metal = v' = $\frac{M'}{d'}$

Difference in volume will give volume of metal ingot.

v' = v - V

$v'=19.73 cm^3-18.08 cm^3=$

$v'=1.65 cm^3$

Since volume cannot be in negative .

Density of the metal =d'

= $d'=\frac{M'}{v'}=\frac{9.5 g}{1.65 cm^3}=5.758 g/cm^3$

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