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Vadim26 [7]
2 years ago
10

What letter on the model titration curve corresponds to the point where ph equals the numerical value of pka for hpr? what speci

es of hpr are present at this point?
Chemistry
1 answer:
irakobra [83]2 years ago
4 0

Letter C on the model titration curve corresponds to the point where pH equals the numerical value of pKa for HPr

<h3>What is a titration curve?</h3>

A titration curve is a graph of the pH of a solution against increasing volumes of an acid or a base that is added to the solution.

The pH of a solution is the negative logarithm to base ten of the hydrogen ion concentration and is a measure of the acidity or alkalinity of the solution.

The pKa is the acid dissociation constant of an acid solution.

In a titration of a strong acid and strong base, the pH at equivalence point is equal to the pKa of the acid.

The equivalence point is the point when equal moles of acids and base has reacted.

In the given titration curve, pH = pKa at point C.

In conclusion, for a titration curve of strong acid and base, at equivalence point, pH is equal to pKa of acid.

Learn more about equivalence point at: brainly.com/question/23502649

#SPJ1

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In writing a chemical equation that produces hydrogen gas, the correct representation of hydrogen gas is
Dennis_Churaev [7]

Answer:

h2

Explanation:

5 0
2 years ago
What is the mass in grams of 5.00moles of CH4?
anastassius [24]

Answer:

1. 80g

2. 1.188mole

Explanation:

1. We'll begin by obtaining the molar mass of CH4. This is illustrated below:

Molar Mass of CH4 = 12 + (4x1) = 12 + 4 = 16g/mol

Number of mole of CH4 from the question = 5 moles

Mass of CH4 =?

Mass = number of mole x molar Mass

Mass of CH4 = 5 x 16

Mass of CH4 = 80g

2. Mass of O2 from the question = 38g

Molar Mass of O2 = 16x2 = 32g/mol

Number of mole O2 =?

Number of mole = Mass /Molar Mass

Number of mole of O2 = 38/32

Number of mole of O2 = 1.188mole

6 0
3 years ago
How many moles of C2H2 are needed to react completely with 84 mol O2
Butoxors [25]

Balanced chemical equation:

2 C2H2 + 5 O2 = 4 CO2 + 2 H2O

2 moles C2H2 ---------------- 5 moles O2
moles C2H2 ------------------ 84 moles O2

moles C2H2 = 84 * 2 / 5

molesC2H2 = 168 / 5 => 33.6 moles of C2H2
4 0
3 years ago
You suspect one of the products of a single replacement is hydrogen gas. How might you experimentally confirm your prediction? C
Nataly_w [17]
The best option i think is b would be my best answer
6 0
3 years ago
What is the Ka of a weak acid (HA) if the initial concentration of weak acid is 4.5 x 10-4 M and the pH is 6.87? (pick one)
rewona [7]

Answer:

Ka = 4.04 \times 10^{-11}

Explanation:

Initial concentration of weak acid = 4.5 \times 10^{-4}\ M

pH = 6.87

pH = -log[H^+]

[H^+]=10^{-pH}

[H^+]=10^{-6.87}=1.35 \times 10^{-7}\ M

HA dissociated as:

HA \leftrightharpoons H^+ + A^{-}

(0.00045 - x)    x     x

[HA] at equilibrium = (0.00045 - x) M

x = 1.35 \times 10^{-7}\ M

Ka = \frac{[H^+][A^{-}]}{[HA]}

Ka = \frac{(1.35 \times 10^{-7})^2}{0.00045 - 0.000000135}

0.000000135 <<< 0.00045

Therefore, Ka = \frac{(1.35 \times 10^{-7})^2}{0.00045 } = 4.04 \times 10^{-11}

5 0
3 years ago
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