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defon
3 years ago
6

Me need help on math:(

Mathematics
1 answer:
sladkih [1.3K]3 years ago
3 0

Answer:

-6 is the answer

Step-by-step explanation:

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"Based on the following construction, which of the following are true? choose all that apply."
umka21 [38]

From the diagram,

Angle

Bisecting an angle means dividing the angle into two equal part.

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4 0
1 year ago
I need help help with this geometry question!
-Dominant- [34]

A property of a parallelogram is that their diagonals bisect eachother. Since in part a the diagonals bisect eachother, we know for sure that it's a parallelogram.

We also know that you can make two congruent triangles with a parallelogram. Note that if you draw a line from one accute angle to the other, we create two equal triangles by SAS congruency, so since the figure is comprised of two congruent triangles, it is a parallelogram.

6 0
3 years ago
B. 21cm 32° L 122° D 0 The perimeter of kite LODI is 74 cm. Find:
Elis [28]

1) Angles IDO and ILO are congruent, and both measure 122 degrees. So, as angles in a quadrilateral add to 360°, angle LOD measures 360-122-122-32=84°

2) As referred to in the first question, angle ODI measures 122°

3) In a kite, there are two pairs of disjoint congruent sides. This means that in this case, ID=IL=21 and LO=OD. As the perimeter is 74, this means LO=(74-21(2))/2=16

4) LI=ID, so ID=21

4 0
2 years ago
An honest die is rolled. If the roll comes out even (2, 4, or 6), you will win $1; if the roll comes out odd (1,3, or 5), you wi
jenyasd209 [6]

Answer:

(a) 50%

(b) 47.5%

(c) 2.5%

Step-by-step explanation:

According to the honest coin principle, if the random variable <em>X</em> denotes the number of heads in <em>n</em> tosses of an honest coin (<em>n</em> ≥ 30), then <em>X</em> has an approximately normal distribution with mean, \mu=\frac{n}{2} and standard deviation, \sigma=\frac{\sqrt{n}}{2}.

Here the number of tosses is, <em>n</em> = 2500.

Since <em>n</em> is too large, i.e. <em>n</em> = 2500 > 30, the random variable <em>X</em> follows a normal distribution.

The mean and standard deviation are:

\mu=\frac{n}{2}=\frac{2500}{2}=1250\\\\\sigma=\frac{\sqrt{n}}{2}=\frac{\sqrt{2500}}{2}=25

(a)

To not lose any money the even rolls has to be 1250 or more.

Since, <em>μ</em> = 1250 it implies that the 50th percentile is also 1250.

Thus, the probability that by the end of the evening you will not have lost any money is 50%.

(b)

If the number of "even rolls" is 1250, it implies that the percentile of 1250 is 50th.

Then for number of "even rolls" as 1300,

1300 = 1250 + 2 × 25

        = μ + 2σ

Then P (μ + 2σ) for a normally distributed data is 0.975.

⇒ 1300 is at the 97.5th percentile.

Then the area between 1250 and 1300 is:

Area = 97.5% - 50%

        = 47.5%

Thus, the probability that the number of "even rolls" will fall between 1250 and 1300 is 47.5%.

(c)

To win $100 or more the number of even rolls has to at least 1300.

From part (b) we now 1300 is the 97.5th percentile.

Then the probability that you will win $100 or more is:

P (Win $100 or more) = 100% - 97.5%

                                   = 2.5%.

Thus, the probability that you will win $100 or more is 2.5%.

7 0
3 years ago
The temperature increased 12°F between 9 AM and noon. It decreased 9°F ° between noon and 6 PM.
bixtya [17]

Answer:

Step-by-step explanation:

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5 0
3 years ago
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