The imidazole side chain of histidine has a pka of 6.04. illustrate the predominant structures for histidine at (i) ph 4, (ii) p
1 answer:
The histidine imidazole side chain has a pka of 6.04. To illustrate the predominant structures for histidine at (i) ph 4, (ii) ph 8, and (iii) ph 12, we have the pictures attached below. The first one indicates structure at ph 4, second one indicates ph 8 and third indicates ph 12.
<h3>What is stereochemistry? </h3>The study of stereochemistry is focused on stereoisomers, which by definition have the same molecular formula and sequence of bonded atoms (constitution) but differ in the three-dimensional orientations of their atoms in space.
Stereochemistry is a subfield of chemistry that deals with the relative spatial arrangement of atoms that form the structure of molecules and their manipulation. Because the prefix “stereo- “denotes “three-dimensionality,” it is also referred to as “3D chemistry.”
One crucial area of stereochemistry is the study of chiral molecules. Stereochemistry covers the entire range of organic, inorganic, biological, physical, and particularly supramolecular chemistry.
The study of stereochemistry involves techniques for identifying and describing these interactions, as well as the impact these relationships have on the physical or biological characteristics of the molecules in question.
To know more about imidazole side chain, Visit:
#SPJ4
You might be interested in
Answer:
The third charge placed is 0.80 m.
Explanation:
Given that,
Distance = 0.57 m
First charge = q
Third charge = 2q
We need to calculate the electrostatic force on charge q₁ due to q₂
Using formula of electrostatic force
When placed another charge q₃ at certain distance from origin, then the net force on charge q₁ due to both charges is
The net electrostatic force on the charge at the origin doubles.
Put the value into the formula
Hence, The third charge placed is 0.80 m from origin in x-axis.
Answer:
Explanation:
We are given that
d=0.23 mm=
Screen is placed from the slits at distance ,L=4.75 m
The bright interference fringes on the screen are separated by 1.56 cm.
1 m=100 cm
We have to find the wavelength of laser light.
We know that
Substitute the values