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Anarel [89]
3 years ago
11

A wave in which particles of the medium move at right angles to the direction of the wave is called a

Physics
1 answer:
Licemer1 [7]3 years ago
5 0

Answer:

transverse wave: A wave in which particles of the medium move at right angles to the direction of the wave is called a transverse wave.

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two negative charge of -2.0 c and a positive charge of 3.0 c are separated by 80 m what is the force between two charges
kozerog [31]
The Coulomb force is equal to the constant k times the product of charge one and charge two over radius.

F=k((q1q2)/r)
6 0
2 years ago
If you know the power rating of an appliance and the current the appliance uses, you can calculate the voltage of the line it is
Helga [31]
If their are choices you should list them. The givens are pretty specific though.

W = E * I is the answer
E (voltage) = W/I is a more refined answer. <<< answer.
7 0
2 years ago
Read 2 more answers
The membrane of a living cell can be approximated by a parallel-plate capacitor with plates of area 4.50×10−9 m2 , a plate separ
Marizza181 [45]

The energy stored in the membrane is 6.44\cdot 10^{-14} J

Explanation:

The capacitance of a parallel-plate capacitor is given by

C=\frac{k\epsilon_0 A}{d}

where

k is the dielectric constant of the material

\epsilon_0 is the vacuum permittivity

A is the area of the plates

d is the separation between the plates

For the membrane in this problem, we have

k = 4.6

A=4.50\cdot 10^{-9} m^2

d=8.1\cdot 10^{-9} m

Substituting, we find its capacitance:

C=\frac{(4.6)(8.85\cdot 10^{-12})(4.50\cdot 10^{-9})}{8.1\cdot 10^{-9}}=2.26\cdot 10^{-11} F

Now we can find the energy stored: for a capacitor, it is given by

U=\frac{1}{2}CV^2

where

C=2.26\cdot 10^{-11} F is the capacitance

V=7.55\cdot 10^{-2} V is the potential difference

Substituting,

U=\frac{1}{2}(2.26\cdot 10^{-11} F)(7.55\cdot 10^{-2})^2=6.44\cdot 10^{-14} J

Learn more about capacitors:

brainly.com/question/10427437

brainly.com/question/8892837

brainly.com/question/9617400

#LearnwithBrainly

6 0
3 years ago
What does the area under the velocity-time graph represent.
V125BC [204]

Answer:

The distance traveled!

Explanation:

This is a velocity time graph of an object moving in a straight line due North.

8 0
2 years ago
Finderkeepers,ismadeormodel
ankoles [38]

Answer:

model lol

Explanation:

7 0
2 years ago
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