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AfilCa [17]
4 years ago
8

An ice cube and a rubber ball are both placed at one end of a warm cookie sheet, and the sheet is then tipped up. The ice cube s

lides down with virtually no friction, and the ball rolls down without slipping. The ball and the ice cube have the same inertia. Which one reaches the bottom first?
Physics
1 answer:
astraxan [27]4 years ago
6 0

Answer:

rubber ball

Explanation:

basically friction is caused by little electrical bonds at a molecular level. the ice had more bonds due to it being a cube rather than a ball which has one point of contact. this means less energy is needed to put the ball in motion than the ice cube.

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Ignacio and Velvet walk eastward with a speed of 8 m/s. If it takes them 7.5 minutes to walk to the store, how far in meters hav
ryzh [129]

Answer:

They walk 3,600 meters

Explanation:

7.5 minutes = 450 seconds.

Because they are walking at 8 meters per 1 second, multiply 8 by 450.

= 3600m

7 0
3 years ago
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The force that keeps objects moving in a circle is called centrifugal force.<br> True<br> False
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Answer: False

Explanation:

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John added 150 grams of salt to 2.5 liters of water. what is the concentration of the salt solutions​
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block with of mass m is at rest on horizontal frictionless surface at time t=0. A force given by F=Bt+C is applied horizontally
Alexeev081 [22]

Answer:

v_{2} =\frac{1}{2}

Explanation:

From the second law of Newton movement laws, we have:

F=m*a, and we know that a is the acceleration, which definition is:

a=\frac{dv}{dt}, so:

F=m*\frac{dv}{dt}\\\frac{dv}{dt}=\frac{F}{m}=\frac{\frac{1}{2}(t+1)}{4}=\frac{t+1}{8}

The next step is separate variables and integrate (the limits are at this way because at t=0 the block was at rest (v=0):

dv=\frac{1}{8}(t+1)dt\\\int\limits^{v_{2}}_0 \, dv=\int\limits^{2}_{0} {\frac{1}{8}(t+1)} \, dt

v_{2}=\frac{1}{8}*(\frac{t^{2}}{2}+t) (This is the indefinite integral), the definite one is:

v_{2}=\frac{1}{8}*(2+2)=\frac{1}{2}

3 0
3 years ago
The spring of a toy car is wound by pushing the car
Zepler [3.9K]

The elastic potential energy stored in the car's spring during the process is 3.75 J

<h3>Determination of the spring constant</h3>

From the question given above, the following data were obtained:

  • Force (F) = 15 N
  • Extention (e) = 0.5 m
  • Spring constant (K) =?

K = F/e

K = 15 / 0.5

K = 30 N/m

<h3>Determination of the potential energy</h3>
  • Spring constant (K) = 30 N/m
  • Extention (e) = 0.5 m
  • Potential energy (PE) =?

PE = ½Ke²

PE = ½ × 30 × 0.5²

PE = 15 × 0.25

PE = 3.75 J

Therefore, the elastic potential energy stored in the car's spring during the process is 3.75 J

Learn more about energy stored in spring:

brainly.com/question/4280346

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2 years ago
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