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AfilCa [17]
4 years ago
8

An ice cube and a rubber ball are both placed at one end of a warm cookie sheet, and the sheet is then tipped up. The ice cube s

lides down with virtually no friction, and the ball rolls down without slipping. The ball and the ice cube have the same inertia. Which one reaches the bottom first?
Physics
1 answer:
astraxan [27]4 years ago
6 0

Answer:

rubber ball

Explanation:

basically friction is caused by little electrical bonds at a molecular level. the ice had more bonds due to it being a cube rather than a ball which has one point of contact. this means less energy is needed to put the ball in motion than the ice cube.

You might be interested in
What happens if you move a bar magnet back and forth along the axis of the
o-na [289]

c. A current is induced in the coiled wire, which lights the light bulb.

<h3></h3><h3>What is electromagnetic induction?</h3>

If we kept the bar magnet stationary and moved the coil back and forth within the magnetic field an electric current would be induced in the coil.

Then by either moving the wire or changing the magnetic field we can induce a voltage and current within the coil and this process is known as Electromagnetic Induction and is the basic principle of operation of transformers, motors and generators.

When the magnet shown below is moved “towards” the coil, the pointer or needle of the Galvanometer, which is basically a very sensitive center zeroed moving-coil ammeter, will deflect away from its center position in one direction only.

When the magnet stops moving and is held stationary with regards to the coil the needle of the galvanometer returns back to zero as there is no physical movement of the magnetic field.

Therefore ,

If you move a bar magnet back and forth along the axis of the coiled wire shown below then a current is induced in the coiled wire, which lights the light bulb.

Learn more about electromagnetic induction here:

brainly.com/question/26334813

#SPJ1

4 0
2 years ago
A 10-kg object is dropped from rest. after falling a distance of 50 m, it has a speed of 26 m/s. what is the change in mechanica
likoan [24]

The change in mechanical energy caused by the dissipative resistance force is equal to, difference between the potential energy and kinetic energy of the object.

Potential energy of the object, P.E = mgh

m is mass of the object = 10 kg

g is acceleration due to gravity = 9.8 m/s²

h= height from which it is dropped =50 m

Substituting the value we get,

P.E = 10×9.8×50 = 4900 J

Kinetic energy of the object, K.E = \frac{1}{2}mv^{2}

v is the velocity of the object = 26 m/s²

K.E = (1/2)×10×(26)²

= 3380 J

Change in mechanical energy caused by dissipative force = P.E ₋ K.E

= 4900 ₋ 3380 = 1520 J

4 0
3 years ago
A mass of 3 slugs (this is the English unit of mass, a pound is a force) is attached to a vertical spring with a spring constant
motikmotik

Answer:

equation of motion for the mass is x(t) = e^αt ( C1 cos √{α² - ω²} t + C2 sin  √{α² - ω²} t )

Explanation:

Given data

mass = 3 slugs = 3 * 32.14 = 96.52 lbs

constant k = 9 lbs/ft

Beta = 6lbs * s/ft

mass is pulled =  1 ft below

to find out

equation of motion for the mass

solution

we know that The mass is pulled 1 ft below so

we will apply here differential equation of free motion i.e

dx²/dt² + 2 α dx/dt + ω² x =0     ........................1

here 2 α  =  Beta / mass

so 2 α  = 6 / 96.52

α  = 0.031

α²  = 0.000961         ...............2

and

ω² = k/mass

ω² = 9 /96.52

ω² = 0.093     ..................3

we can say that from equation 2 and 3 that α² - ω²  = -0.092239

this is less than zero

so differential equation is

x(t) = e^αt ( C1 cos √{α² - ω²} t + C2 sin  √{α² - ω²} t )

equation of motion for the mass is x(t) = e^αt ( C1 cos √{α² - ω²} t + C2 sin  √{α² - ω²} t )

3 0
3 years ago
Can water and wind change the shape of a mountain
Art [367]

Answer:

Yes, through erosion.

Explanation:

Water, wind, and ice shape earths surface. Water, wind, & ice move sediment to another area this process is called erosion.

Mark me brainliest, hope this helps

4 0
3 years ago
Points A and B lie within a region of space where there is a uniform electric field that has no x- or z-component; only the y-co
liraira [26]

Answer:

(a) Ey is negative

(b) The magnitude of the electric field is E = 171.429 V/m

(c) The potential difference between points B and C is 17.1429 V

Explanation:

(a) Here, we have the potentials given by;

V_A - V_B = +12.0V with point A at y = 8.00 cm and point B at point y = 15.0 cm

where point B is at a higher potential than point A, that is the electric potential is from;

B with y = 15.0 cm to A with y = 8.0 cm which means

E_y decreases as y increases or E_y  is negative.

(b) The magnitude of the electric field is given by

The work done to move a charge from B to A is

W_{BA} = - \Delta U where

\Delta U = U_a -U_b = q_0E(y_b-y_a)

V_{BA} = \frac{\Delta U}{q_0} = \frac{q_0E(y_b-y_a)}{q_0}  = E(y_b-y_a)

∴ E = \frac{V_{BA}}{(y_b-y_a)}

E = \frac{12 \hspace{0.09cm}V}{(0.015\hspace{0.09cm} m -0.008\hspace{0.09cm} m)}

E = 171.429 V/m

(c) Here we have point C x = 5.00 cm and y = 5.00 cm

Therefore we have the distance from B to C given by

y_b-y_c = 15.00 \hspace{0.09cm}cm - 5.00  \hspace{0.09cm}cm = 10.00 \hspace{0.09cm} cm

Where 10.00 cm = 0.01 m

E = V/Δy

Therefore, V = Δy·E

For V_{BC}, Δy = y_b-y_c  = 0.01 \hspace{0.09cm} m and we have,

V_{BC} = E\times (y_b-y_c)

V_{BC} = 171.429\times (0.015-0.005) = 17.1429\hspace{0.09cm}V

7 0
3 years ago
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