Question

Please help me determine the pH for these solutions:[H+]=6.27x10^-7MAnd[OH-]=3.4x10^-13

Answer 1

Answer

For [H+] ---> pH = 6.2

For [OH-] ---> pH = 1.53

Explanation

Given:

[H+]=6.27x10^-7M

[OH-]=3.4x10^-13

Required: Calculate pH

Solution:

$pH\text{ = -log\lbrack H}_3O^+]$

For [H+]=6.27x10^-7M

pH = -log[6.27x10^-7]

pH = 6.2

For [OH-]=3.4x10^-13

14 = pH + pOH

pH = 14 + log[OH-]

pH = 14 + log [3.4x10^-13]

pH = 1.53