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sladkih [1.3K]
3 years ago
9

Show that, with appropriate coefficients, the two reactions can be summed to give the overall oxidation of SO2 by O2 to give SO3

. Give the equation for the final overall oxidation of SO2 by O2 to give SO3 as your answer.
Chemistry
1 answer:
Llana [10]3 years ago
5 0

Explanation:

It is known that the oxidation of SO_{2} to SO_{3} is catalyzed by NO_{2} . In this process, two steps are involved as follows.

(a)    NO_{2}(g) + SO_{2}(g) \rightarrow NO(g) + SO_{3}(g)

whereas, the second step is

(b)    2NO(g) + O_{2}(g) \rightarrow 2NO_{2}(g)

Balancing the above reaction by multiplying equation (a) by 2 as follows.

(c)    2NO_{2}(g) + 2SO_{2}(g) \rightarrow 2NO(g) + 2SO_{3}(g)

Now, on adding both  reaction equations (b) and (c) the net reaction equation will be as follows.

        2SO_{2}(g) + O_{2}(g) \rightarrow 2SO_{3}(g)


Thus, we can conclude that the equation for the final overall oxidation of SO_{2} by O_{2} to give SO_{3} is as follows.

             2SO_{2}(g) + O_{2}(g) \rightarrow 2SO_{3}(g)


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3 years ago
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How many grams of KBr are required to make 350. mL of a 0.115 M KBr solution?
Vsevolod [243]
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6 0
4 years ago
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Cuales elementos tienen solo un electrón de valencia ​
aleksley [76]

Answer:

En el caso del sodio, la valencia es 1, ya que tiene un solo electrón de valencia, si pierde un electrón se queda con el último nivel completo.

Explanation:

Grupo de la tabla periódica Electrones de valencia

Grupo 14 (IV) (Grupo del carbono) 4

Grupo 15 (V) (Grupo del nitrógeno ) 5

6 0
3 years ago
An analysis of a sugar compound is found to contain 132 grams of carbon (C), 22 grams of hydrogen (H), and 176 grams of oxygen (
ddd [48]
132 g of C  ,   22 g of H   , 176 g of O

132 + 22 + 176 => 330 g <span>of the substance

</span>Now convert the masses in <span>moles :
</span>
C = 12.0 u        H = 1.0 u       O = 16.0 u

C = 132 / 12.0 => 11 moles

H = 22 / 1.0 => 22 moles

O = 176 / 16.0 => 11 moles

Using the values obtained the lowest proportion in mols of elements present, simply divide the values found for the least of them<span>:
</span>
C = 11 / 11 => 1

H = 22 / 11 => 2

O = 11 / 11 => 1

 formula empirically <span>is : CH</span>₂O

hope this helps!


8 0
4 years ago
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