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makkiz [27]
3 years ago
9

What volume of oxygen (O2) gas is equal to 4.5 moles at STP?

Chemistry
2 answers:
Aleks04 [339]3 years ago
8 0

Answer:

molar volume of gas

Explanation:

skelet666 [1.2K]3 years ago
4 0

Answer: 100.8L

Explanation:

1mole of O2 occupies 22.4L at stp

Therefore, 4.5 moles of O2 will occupy = 4.5 x 22.4 = 100.8L

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7 0
3 years ago
If the concentration of Mg2+ in the solution were 0.039 M, what minimum [OH−] triggers precipitation of the Mg2+ ion? (Ksp=2.06×
Elodia [21]

Answer:

2.30 × 10⁻⁶ M

Explanation:

Step 1: Given data

Concentration of Mg²⁺ ([Mg²⁺]): 0.039 M

Solubility product constant of Mg(OH)₂ (Ksp): 2.06 × 10⁻¹³

Step 2: Write the reaction for the solution of Mg(OH)₂

Mg(OH)₂(s) ⇄ Mg²⁺(aq) + 2 OH⁻(aq)

Step 3: Calculate the minimum [OH⁻] required to trigger the precipitation of Mg²⁺ as Mg(OH)₂

We will use the following expression.

Ksp = 2.06 × 10⁻¹³ = [Mg²⁺] × [OH⁻]²

[OH⁻] = 2.30 × 10⁻⁶ M

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