Question

If (2 +3i)^2 + (2 - 3i)^2 = a + bia =b=

Answer 1

(2 + 3i)^2 = 4 + 12i + 9(-1)

= 4 + 12i - 9

= -5 + 12i

(2 - 3i)^2 = 4 - 12i - 9(-1)

= 4 - 12i + 9

= 13 - 12i

REsult

= -5 + 12i + 13 - 12i

= 8 - 0i

Then

a = 8 and b = 0