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11 months ago

Look at thetriangles diagram. The value of x is ___ °

Mathematics

1 answer:

NemiM [27]11 months ago

4 0

By solving a linear equation we will see that the value of x is 10.

<h3></h3><h3>How to find the value of x?</h3>

Remember that for any triangle, the sum of all internal angles is always equal to 180°.

Here only look at triangle BCD, we know that:

m∠DBC = m∠ABC = 3x

m∠BCD = m∠ACB + m∠ABD = 2x + 65°

m∠ADC = 65°

Now we can write the linear equation as:

3x + 2x + 65° + 65° = 180°

5x + 130° = 180°

5x = 180° - 130°

5x = 50°

x = 50°/5 = 10°

The value of x is 10.

Learn more about triangles:

brainly.com/question/14285697

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Complete Question

The complete question is shown on the first uploaded image

Answer:

$g(h(x)) = \sqrt[4]{x^2 + x +5} + 3$

$h(g(x)) = \sqrt{x} + 7\sqrt[4]{x} + 17$

$h(h(x)) = [x^2 + x + 5 ]^2 + x^2 + x + 10$

Step-by-step explanation:

From the question we are told that

$h(x) = x^2 + x + 5$

and

$g(x) = \sqrt[4]{x} + 3$

Considering first question

Now we are told g(h(x))

i.e

$g(h(x)) = [x^2 + x + 5 ]^{\frac{1}{4} } + 3$

=> $g(h(x)) = \sqrt[4]{x^2 + x +5} + 3$

Considering second question

Now we are told h(g(x))

i.e

$h(g(x)) = [x^{\frac{1}{4} } + 3]^2 + x^{\frac{1}{4} } + 3 + 5$

=> $h(g(x)) = x^{\frac{1}{2} } + 6x^{\frac{1}{4} } + 9+ x^{\frac{1}{4}} + 8$

=> $h(g(x)) = x^{\frac{1}{2}} + 7x^{\frac{1}{4}} + 17$

=> $h(g(x)) = \sqrt{x} + 7\sqrt[4]{x} + 17$

Considering third question

$h(h(x))= [x^2 + x + 5]^2 + [x^2 + x + 5 ] + 5$

=> $h(h(x)) = [x^2 + x + 5 ]^2 + x^2 + x + 10$

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