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svetlana [45]
1 year ago
14

when 1.00 mol co and 3.00 mol h2 are placed into a 10.0 l vessel at 9270c and allowed to come to equilibrium, the mixture is fou

nd to contain .387 mol h2o at equilibrium. what is the concentration of each substance at equilibrium? what is the kc for this reaction at 9270c?
Chemistry
1 answer:
Olin [163]1 year ago
6 0

The largest value of w (in N)that they can support as shown in equilibrium.

What is equilibrium?

a State of balance between opposing forces or actions that is either static as in nobody acted on by forces whose resultant is zero or dynamic reaction when the rates of reaction in both differentions are equal.

Sol- the total force in x direction is given as,

€Fx=0

T1 sin 37°=T2 sin 53°

100×3/5 =T/2 ×4/5

T2=75 N

The given total force is-

€Fy=0

T1 cos 37°=T2 cos 53°+W

W=80×4/5 -75×3/5

W=19N

Thus

The largest value of W is 19N.

To know more about equilibrium click-

brainly.com/question/517289

#SPJ4

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What it the oxidation number for cl?<br> A. -2<br> B. +2<br> C. -1<br> D. +1
brilliants [131]

Answer:

c.

Explanation:

it is c.-1 because oxidation number of cl is-1

5 0
3 years ago
A voltaic cell is based on the following two half-reactions: ni 2(aq) 2e− → ni(s) e° = −0. 25 v cr 3(aq) 3e– → cr(s) e° = –0. 74
emmasim [6.3K]

The net cell reaction is given as 3 Ni²⁺ (aq) + 2 Cr (s) = 2 Cr³⁺ (aq) + 3 Ni (s), and the cell potential is 0.49 V.

<h3>What is a half-cell reaction?</h3>

A half cell reaction is given as the oxidation or the reduction reaction that takes place at each of the anode or the cathode, forming the net redox reaction.

The cell potential and the half-reactions are:

Ni²⁺ + 2e⁻ = Ni (s)     E° = -0.25 V

Cr³⁺ + 3e⁻ = Cr (s)     E° = -0.74 V

The anodic reaction is given as:

Cr (s) = Cr³⁺ + 3e⁻     E° = 0.74 V

The cathodic reaction is given as:

Ni²⁺ + 2e⁻ = Ni (s)     E° = -0.25 V

Thus, the net reaction of the cell will be:

3 Ni²⁺ (aq) + 2 Cr (s) = 2 Cr³⁺ (aq) + 3 Ni (s)

The cell potential can be calculated as:

E° = E (cathode) + E (anode)

E° = 0.74 + (-0.25) V

E° = 0.49 V

Thus, the net cell reaction is given as 3 Ni²⁺ (aq) + 2 Cr (s) = 2 Cr³⁺ (aq) + 3 Ni (s), and the cell potential is 0.49 V.

Learn more about cell potential, here:

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3 0
2 years ago
What is the pH of a solution with a 7.8 × 10−13 M hydronium ion concentration?
Helga [31]

Answer:

D. 12

Explanation:

The pH is a measure of the acidity of a solution. The pH indicates the concentration of hydronium ions [H3O +] present in a solution;

pH = - log [H3O+]

So

pH= - log [7.8 × 10−13 M]

finally

pH= 12

6 0
3 years ago
Read 2 more answers
Calculate ΔS° for the reaction: 4Cr(s) + 3O2(g) → 2Cr2O3(s), Substance: Cr(s) O2(g) Cr2O3(s), S°(J/K⋅mol): 23.77 205.138 81.2
Mariana [72]

<u>Answer:</u> The value of \Delta S^o for the reaction is 1051.93 J/K

<u>Explanation:</u>

Entropy change is defined as the difference in entropy of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate entropy change is of a reaction is:

\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{(product)}]-\sum [n\times \Delta S^o_{(reactant)}]

For the given chemical reaction:

4Cr(s)+3O_2(g)\rightarrow 2Cr_2O_3(s)

The equation for the entropy change of the above reaction is:

\Delta S^o_{rxn}=[(2\times \Delta S^o_{(Cr_2O_3(s))})]-[(4\times \Delta S^o_{(Cr(s))})+(3\times \Delta S^o_{(O_2(g))})]

We are given:

\Delta S^o_{(Cr_2O_3(s))}=881.2J/K.mol\\\Delta S^o_{(O_2(g))}=205.13J/K.mol\\\Delta S^o_{(Cr(s))}=23.77J/K.mol

Putting values in above equation, we get:

\Delta S^o_{rxn}=[(2\times (881.2))]-[(4\times (23.77))+(3\times (205.13))]\\\\\Delta S^o_{rxn}=1051.93J/K

Hence, the value of \Delta S^o for the reaction is 1051.93 J/K

5 0
4 years ago
MYTH OR FACT? Eating disorders occur only in fernales. *
sdas [7]

Answer:

myth

Explanation:

3 0
3 years ago
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