Proton:
Positively charged
Inside nucleus
Mass - 1
Electrons:
Negatively charged
Outside the nucleus
Mass - 1/2000
<em>n</em> = 15. A Bohr orbit with <em>n</em> = 15 comes closest to having a 24 nm diameter
.
The formula for the radius <em>r</em> of the <em>n</em>th orbital of a hydrogen atom is
<em>r</em> = <em>n</em>^2·<em>a</em>
where
<em>a</em> = the Bohr radius = 0.0529 nm
We can solve this equation to get
<em>n</em> = √ (<em>r</em>/<em>a</em>)
If <em>d</em> = 24 nm, <em>r</em> = 12 nm.
∴ <em>n</em> = √(12 nm/0.0529 nm) = √227 = 15.1
<em>n</em> must be an integer, so <em>n</em> = 15.
It is a controlled experiment
<h3><u>Answer and explanation</u>;</h3>
- To balance the charges of ions the number of electrons lost is equal to the number of electrons gained. The overall net charge must be zero.
- The number of ions needed to accomplish this is represented by the subscripts.
- For any given ionic compound, the product of the charge on the ion (or multiatomic ionic group) times the subscript of the ion will give a total charge of zero when all ions are considered.
For examples: NaCl Na = +1 Cl = -1 total is zero
