1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Aloiza [94]
3 years ago
14

When a hydrogen atom makes the transition from the second excited state to the ground state (at -13.6 eV) the energy of the phot

on emitted is:
Chemistry
1 answer:
viktelen [127]3 years ago
3 0

Answer : The energy of the photon emitted is, -12.1 eV

Explanation :

First we have to calculate the 'n^{th}' orbit of hydrogen atom.

Formula used :

E_n=-13.6\times \frac{Z^2}{n^2}ev

where,

E_n = energy of n^{th} orbit

n = number of orbit

Z = atomic number  of hydrogen atom = 1

Energy of n = 1 in an hydrogen atom:

E_1=-13.6\times \frac{1^2}{1^2}eV=-13.6eV

Energy of n = 2 in an hydrogen atom:

E_3=-13.6\times \frac{1^2}{3^2}eV=-1.51eV

Energy change transition from n = 1 to n = 3 occurs.

Let energy change be E.

E=E_-E_3=(-13.6eV)-(-1.51eV)=-12.1eV

The negative sign indicates that energy of the photon emitted.

Thus, the energy of the photon emitted is, -12.1 eV

You might be interested in
Ozone gas is a form of elemental oxygen containing molecules with three oxygen atoms, O3. Ozone is produced from atmospheric oxy
adelina 88 [10]

<u>Answer:</u> The unbalanced chemical equation is written below

<u>Explanation:</u>

Unbalanced chemical equation does not follow law of conservation of mass.

In an unbalanced chemical equation, total number of individual atoms on the reactant side will not be equal to the total number of individual atoms on the product side.

The chemical equation for the formation of ozone gas from oxygen gas:

O_2(g)\rightarrow O_3(g)

Hence, the unbalanced chemical equation is written above.

8 0
3 years ago
Read 2 more answers
What is the molarity of an hno3 solution if 51.0 ml is needed to react with 25.0 ml of 0.150 mkoh solution? the equation is hno3
artcher [175]
<span>The  Answer </span>should be<span> .074 M</span>
6 0
3 years ago
Students were asked to identify the location of elements in the
Naddika [18.5K]

Answer:амьсгал боогдов гэж найдаж байна

Explanation:

4 0
3 years ago
In the equilibrium constant expression for the reaction below what is the correct exponent for N2O4?
irga5000 [103]
As we have the balanced reaction equation is:

N2O4 (g) ↔ 2NO2(g)

from this balanced equation, we can get the equilibrium constant expression

KC = [NO2]^2[N2O4]^1

from this expression, we can see that [NO2 ] is with 2 exponent of  the stoichiometric and we can see that from the balanced equation as NO2
is 2NO2 in the balanced equation.

and [N2O4] is with 1 exponent of the stoichiometric and we can see that from the balanced equation as N2O4 is 1 N2O4 in the balanced equation. 

∴ the correct exponent for N2O4 in the equilibrium constant expression is 1 
7 0
3 years ago
How many moles of CaCl₂ are required to produce 45.97 grams of NaCl?
marin [14]
Answer is 0.7866187543

6 0
2 years ago
Other questions:
  • Where would you find the element with least mass?
    13·1 answer
  • When K2SO4 is separated into its ions, how is it written?
    15·2 answers
  • What size container should you use when mixing chemicals
    7·1 answer
  • What is the temperature of a 100 liter container having 1 mole of an ideal gas at a pressure of 20 kilopascals? (Given: R = 8.31
    13·1 answer
  • A sample of an unknown compound has a percent composition of 52.14% carbon, 13.13% hydrogen, and 34.73% oxygen. Which compounds
    10·2 answers
  • 8 Which elements have the most similar chemical properties?
    13·2 answers
  • Consider the ammonolysis of benzoyl chloride by adding concentrated ammonium hydroxide to form the final product, benzamide. Rea
    9·1 answer
  • The scientific method is ___ <br>a. linear<br>b. cyclic​
    10·1 answer
  • Help me please TwT. I really need it TwT
    7·1 answer
  • The average atomic mass of carbon is 12.01 amu. Based on the atomic
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!