Question

The molarity of a sodium hydroxide (NaOH) solution is 0.2 M. The molar mass of NaOH is 40 g/mol. If the solution contains 20 g of sodium hydroxide dissolved in water, what is the volume of the solution? brainly

Answer 1

Answer:

$\large \boxed{\text{2.5 L}}$

Explanation:

1. Calculate the moles of NaOH.

$\text{Moles} = \text{20 g} \times \dfrac{\text{1 mol}}{\text{40 g}} = \text{0.50 mol}$

2. Calculate the volume of NaOH

$\begin{array}{rcl}\\\text{Molar concentration} &= &\dfrac{\text{moles}}{\text{litres}}\\\\ n &= &\dfrac{c}{V}\\\\\dfrac{\text{0.2 mol}}{\text{1 L}} &=& \dfrac{\text{0.50 mol}}{V}\\\\ \dfrac{0.2V}{\text{1 L}} & = & 0.50\\\\0.2V &= & \text{0.50 L}\\V & = & \dfrac{\text{0.50 L}}{0.2}\\\\& = & \textbf{2.5 L}\\\end{array}\\\text{The volume of the solution is \large \boxed{\textbf{2.5 L}} }$

Answer 2

Answer:

The 0.2M NaOH solution has a volume of 2.5 L

Explanation:

Step 1: Data given

Molarity of a NaOH solution = 0.2 M

Molar mass of NaOH = 40 g/mol

Mass of NaOH = 20.00 grams

Step 2: Calculate moles of NaOH

Moles = mass / molar mass

Moles NaOH = 20.00 grams / 40 g/mol

Moles NaOH = 0.50 moles

Step 3: Calculate volume

Molarity = moles / volume

Volume of solution = moles of NaOH / Molarity

Volume of solution = 0.50 moles / 0.2 M

Volume of solution = 2.5 L

The 0.2M NaOH solution has a volume of 2.5 L