Which element easily loses one electron to form a positive ion? (AKS 1c/DOK 1)
1 answer:
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Solution :
When non volatile solute is added to solvent, vapor pressure gets lowered.
Relative lowering in vapor pressure is given :
=
of solute
= vapor pressure of pure solvent
P = vapor pressure of solution
= mole fraction of solute
=
=
Number of moles
1. For 10 g of
Ions = 2
It will affect colligative property.
Relative lowering in vapor pressure will be :
2. For 20 g sucrose
Sucrose is non electrolyte, i = 1
3. For 20 g of glucose.
Glucose is a non electrolyte, i = 1
is same in all three solutions.
Hence, lowering in vapor pressure is maximum in and minimum is Sucrose.
Vapor pressure from lowest to highest.
10 g of < 20 g of glucose < 20 g of sucrose
Answer:
2.76 × 10⁻¹¹
Explanation:
I don’t have access to the ALEKS Data resource, so I used a different source. The number may be different from yours.
1. Calculate the free energy of formation of CCl₄
C(s)+ 2Cl₂(g)→ CCl₄(g)
ΔG°/ mol·L⁻¹: 0 0 -65.3
ΔᵣG° = ΔG°f(products) - ΔG°f(reactants) = -65.3 kJ·mol⁻¹
2. Calculate K
T = (25.0 + 273.15) K = 298.15 K