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1 year ago

Round the decimal to the nearest tenth 0.709

Mathematics

1 answer:

Inessa [10]1 year ago

8 0

Given:-

$0.709$

To find the nearest tenth.

Since the tenths term is greater than five the nearest tenths is,

$1.000$

So the required is 1.00

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What is the area of the shaded region? Use 3.14 for pi and round to the nearest tenth.

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Step-by-step explanation:

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4 years ago

: If tan A=- 9/13 and 0 < A < 180, find, without using tables or calculators, the value of

stich3 [128]

Answer: $\bold{\sin A=\dfrac{9\sqrt{10}}{50}\qquad \cos A=-\dfrac{13\sqrt{10}}{50}}$

<u>Step-by-step explanation:</u>

0° < A < 180° so it is in Quadrant I or II

since tan A is negative, it is in Quadrant II ---> (-x, +y)

$\text{Given}:\tan A=\dfrac{y}{x}\ =\dfrac{9}{-13}$

Next, find the hypotenuse given that x = -13 and y = 9

(-13)² + (9)² = r²

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$\sin A = \dfrac{y}{r}\quad =\dfrac{9}{5\sqrt{10}}\bigg(\dfrac{\sqrt{10}}{\sqrt{10}}\bigg)\quad =\large\boxed{\dfrac{9\sqrt{10}}{50}}\\\\\\\\\cos A = \dfrac{x}{r}\quad =\dfrac{-13}{5\sqrt{10}}\bigg(\dfrac{\sqrt{10}}{\sqrt{10}}\bigg)\quad =\large\boxed{-\dfrac{13\sqrt{10}}{50}}$

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3 years ago

Find x (x+13)(x-7)=0

alex41 [277]

So for this, we will be applying the <u>zero product property</u>, which is <u>"if a x b = 0, then either a = 0 or b = 0 or both a and b = 0"</u>. In this case, a = x + 13 and b = x - 7. Solve them separately:

$x+13=0\\ x=-13\\ \\ x-7=0\\ x=7$

<u>Your answer is x = -13 and 7.</u>

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icang [17]

<h3>Answer: k^2*p^6</h3>

Work Shown:

s = length of each side

s = kp^3

A = area of square

A = s^2

A = s*s

A = (kp^3)*(kp^3)

A = (k*k)*(p^3*p^3)

A = k^2*p^6

To multiply the terms, you add the exponents. Think of k as k^1, so k*k = k^1*k^1 = k^(1+1) = k^2

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3 years ago