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expeople1 [14]
2 years ago
8

How long does it take for a bowling ball to fall 1m?

Physics
1 answer:
Tcecarenko [31]2 years ago
3 0

1. It will take 0.45 s for the bowling ball to fall 1 m

2. it will take 0.45 s for the ping pong ball to fall 1 m

<h3>Data obtained from the question</h3>

From the question given above, the following data were obtained:

  • Height (h) = 1 m
  • Acceleration due to gravity (g) = 9.8 m/s²
  • Time (t) =?

<h3>How to determine the time taken to fall</h3>

The time taken for the bowling ball to fall can be obtained as illustrated below:

h = ½gt²

1 = ½ × 9.8 × t²

1 = 4.9 × t²

Divide both side by 4.9

t² = 1 / 4.9

Take the square root of both side

t = √(1 / 4.9)

t = 0.45 s

Thus, it will take 0.45 s for the bowling ball to fall.

Considering the ping pong ball, it will also take 0.45 s to fall 1 m since the same gravity is acting on it

Learn more about motion under gravity:

brainly.com/question/22719691

#SPJ1

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Answer:

a circular path

Explanation:

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F = V\times B

According to the property of cross-product, the Lorentz force (F) acting on the particle will be perpendicular to the instantaneous position of the particle, making the path of the particle to be a circular path.

3 0
3 years ago
A 75kg man goes up a tower 30 m in 120s. How much power did the man exert
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Explanation:

If g= 10m/s²

Then 75kg=75×10=750N

Since Work =Force ×Distance

Work=750×30

=22500J

And Power°=Work÷time

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=187.5W

8 0
3 years ago
A rubber ball moving at a speed of 5 m/s hit a flat wall and returned to the thrower at 5 m/s. Which statement
Step2247 [10]

Answer:

d. Its magnitude and its direction both remained the same.

Explanation:

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

Momentum = mass * velocity

The law of conservation of momentum states that the total linear momentum of any closed system would always remain constant with respect to time.

This ultimately implies that, the law of conservation of momentum states that if objects exert forces only on each other, their total momentum is conserved.

In this scenario, a rubber ball moving at a speed of 5 m/s hit a flat wall and returned to the thrower at 5 m/s. Thus, the statement which correctly describes the momentum of the rubber ball is that its magnitude and its direction both remained the same because its velocity didn't change while returning to the thrower.

4 0
3 years ago
A grocery shopper tosses a(n) 9.0 kg bag of rice into a stationary 17.4 kg grocery cart. The bag hits the cart with a horizontal
noname [10]

Answer:

V=1.77m/s

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Hence:

9.0\times 5.2+17.4\times 0=(9+17.4)V\\\\V=\frac{9\times5.2}{9+17.4}\\\\=1.77m/s\\

Hence, the final velocity of the cart and bag is 1.77m/s

7 0
4 years ago
I am really struggling with this question because I can't find anything on aphelion and perihelion, it's not a topic we went ove
Hoochie [10]

I have a strange hunch that there's some more material or previous work
that goes along with this question, which you haven't included here.

I can't easily find the dates of Mercury's extremes, but here's some of the
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</span> </span> </span> <span> Distance at Perihelion (</span></span><span>point in it's orbit that's closest to the sun):</span>
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</span><span>Mercury's Orbital period = <span><span>87.9691 Earth days</span></span></span></span>

1/2 (50%) of that is  43.9845  Earth days

The average of the aphelion and perihelion distances is

     1/2 ( 69,816,900 + 46,001,200 ) = 57,909,050 km
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