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3 years ago

10

n the problem 5 divided by one-half, Joanne and Oliver are finding how many halves are in 5. What picture could you draw to repr

esent this problem?

2 answers:

Illusion [34]3 years ago

8 0

Answer:

I would draw a pizza with 5 slices, then cut the slices in half.

Step-by-step explanation:

madam [21]3 years ago

6 0

there are 10 halves in 5 pizzas because 5 divided by 0.5

so just say like there are 10 pizza halves

hope i helped

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Use the arc length formula to find the length of the curve y = 4x − 5, −1 ≤ x ≤ 3. Check your answer by noting that the curve is

Reptile [31]

Answer:

$4\sqrt{17}$

Step-by-step explanation:

Let's find the answer by using the arc length formula which is:

$\int\limits^a_b {\sqrt{1+(\frac{dy}{dx})^{2} } } \, dx$

First, let's find dy/dx which is:

y=4x-5

y'=4*(1)-0

y'=4, now let's use the formula:

$\int\limits^3_{-1} {\sqrt{1+4^{2}} } \, dx=\sqrt{17} *(3-(-1))=4\sqrt{17}$

Now, using the distance formula we have:

$d=\sqrt{(x2-x1)^{2} +(y2-y1)^{2} }$

$y(-1)=4*(-1)-5=-9 \\y(3)=4*(3)-5=7$

So we have two points (-1, -9) and (3, 7) so:

$d=\sqrt{(3-(-1))^{2} +(7-(-9))^{2} }=4\sqrt{17}$

Notice both equations gave the same length $4\sqrt{17}$ .

5 0

3 years ago

Hey yall sorry that im pretty stupid but can you answer this whats 9x = 7 ( x + 2)

Yuliya22 [10]

Answer:

x=7

Step-by-step explanation:

1. Distribute

2. Subtract 7x from both sides of the equation

3. Simplify

4. Divide both sides of the equation by the same term

5. Simplify

Answer: x=7

5 0

2 years ago

Read 2 more answers

For a quadratic equation where: 2++=0

otez555 [7]

Answer:

Solutions will be unreal

Step-by-step explanation:

Given the quadratic equation ax^2+bx+c

The discriminant of the function determines its nature of its root

Discriminant D = b^2-4ac

If D <0, it shows that the roots of the equation will be a complex value. since D is less than 0 and the square root of a negative number does not exist. Hence, the solutions will be unreal

3 0

2 years ago

HELP! WILL MARK BRAINLIEST IF CORRECT!

mariarad [96]

I think it’s 25???? i tried haha

8 0

2 years ago

A university found that 20% of its students withdraw without completing the introductory statistics course. Assume that 20 stude

EleoNora [17]

Answer:

a) $P(X \leq 2)= P(X=0)+P(X=1)+P(X=2)$

And we can use the probability mass function and we got:

$P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115$

$P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576$

$P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369$

And adding we got:

$P(X \leq 2)=0.0115+0.0576+0.1369 = 0.2061$

b) $P(X=4)=(20C4)(0.2)^4 (1-0.2)^{20-4}=0.2182$

c) $P(X>3) = 1-P(X \leq 3) = 1- [P(X=0)+P(X=1)+P(X=2)+P(X=3)]$

$P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115$

$P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576$

$P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369$

$P(X=3)=(20C3)(0.2)^3 (1-0.2)^{20-3}=0.2054$

And replacing we got:

$P(X>3) = 1-[0.0115+0.0576+0.1369+0.2054]= 1-0.4114= 0.5886$

d) $E(X) = 20*0.2= 4$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=20, p=0.2)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Part a

We want this probability:

$P(X \leq 2)= P(X=0)+P(X=1)+P(X=2)$

And we can use the probability mass function and we got:

$P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115$

$P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576$

$P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369$

And adding we got:

$P(X \leq 2)=0.0115+0.0576+0.1369 = 0.2061$

Part b

We want this probability:

$P(X=4)$

And using the probability mass function we got:

$P(X=4)=(20C4)(0.2)^4 (1-0.2)^{20-4}=0.2182$

Part c

We want this probability:

$P(X>3)$

We can use the complement rule and we got:

$P(X>3) = 1-P(X \leq 3) = 1- [P(X=0)+P(X=1)+P(X=2)+P(X=3)]$

$P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115$

$P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576$

$P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369$

$P(X=3)=(20C3)(0.2)^3 (1-0.2)^{20-3}=0.2054$

And replacing we got:

$P(X>3) = 1-[0.0115+0.0576+0.1369+0.2054]= 1-0.4114= 0.5886$

Part d

The expected value is given by:

$E(X) = np$

And replacing we got:

$E(X) = 20*0.2= 4$

3 0

2 years ago