Let r = usual driving rate
let t = usual driving time
We need to figure out t
The distance she covers in her usual time at her usual rate is r*t
The distance she covers in her new time at her new rate is:
(1+t)*((2/3)r)
Set this equal to each other and solve for t.
rt = (2/3)r + (2/3)rt
(1/3)rt = (2/3)r
(1/3)t = (2/3)
t = 2
So her usual time is 2 hours. (There's probably a faster way to do this)
9514 1404 393
Answer:
1 1/5
Step-by-step explanation:
We want to find the number of times (5/6) goes into 1, so we divide ...
1/(5/6) = 1 × 6/5 = 6/5 = 1 1/5
There are 1 1/5 groups of 5/6 in 1.
_____
<em>Another way to look at it</em>
You can consider 1 to be divided into 6 equal part:
o o o o o o
We can group these in groups of 5, so each group is 5/6 of the whole:
(o o o o o) o
What we see is that we have 1 group, and 1/5 of another group.
That is, 1 has 1 1/5 groups of 5/6 in it.
Answer:
The measure of angle AGF is
Step-by-step explanation:
Let
x------> the measure of angle CGD
y------> the measure of angle BGC
we know that
-----> equation A
-----> equation B
Substitute equation B in equation A and solve for y
Find the value of x
The measure of angle CGD is
m<AGF=m<CGD -------> by vertical angles
therefore
The measure of angle AGF is
Answer:
210 is volume
Step-by-step explanation:
volume is equal to length times Width times Height
8 1/3 times 4 1/5 time 6
= 210
have a wonderful day!