The mole fraction of ethanol c2h5oh in an aqueous solution that is 46 percent ethanol by mass is 0.25
Mole fraction is the mole of one of the component of the solution divided by the total moles of the solution
Calculating the mole fraction of ethanol,we get
Percentage by weight of ethyl alcohol is 46% which implies in 100 g of this solution is 46 g while the mass of the water will be 54% of 100 g = 54g.
Finding the moles of water and the ethyl alcohol {molar mass of water(H₂O) = 18 and molar mass of ethyl alcohol(C₂H₆O = 46}
Moles = mass/molar mass
moles of ethanol = 46/46 = 1
moles of water = 54/18 = 3
ntotal=1+3=4
Mole fraction of ethanol is:
Mole of ethanol = 1/4
Total mole of solution
Hence, the mole fraction is 1/4 or 0.25
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