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daser333 [38]
3 years ago
11

Sunny makes a poster showing the levels of

Chemistry
2 answers:
ZanzabumX [31]3 years ago
8 0

Answer:

it is the 4th and 5th one

Explanation:

i did it

Vladimir [108]3 years ago
5 0

Answer:

3rd and 5th!

Explanation:

:)

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Which of the following is closest to the meaning of the term ancestor?
rjkz [21]

Answer:

I would say A

Explanation:

our ancestors are the people that lived long before us

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If an element has 4 naturally occuring isotopes, how many peaks will show up in the mass spectra?
BartSMP [9]

Base peak: The most intense (tallest) peak in a mass spectrum, due to the ion with the greatest relative abundance (relative intensity; height of peak along the spectrum's y-axis). Not to be confused with molecular ion: base peaks are not always molecular ions, and molecular ions are not always base peaks.

6 0
2 years ago
can Someone please do this for me i did like one but i dont understand the rest please please please i beg i need it for tommoro
kobusy [5.1K]
How do you solve x = 4 + 9x
5 0
3 years ago
Scott is conducting a lab experiment when his lab paper catches on fire! Scott, knowing his safety procedures, heads towards the
LuckyWell [14K]

Answer:

Contact with corrosive substances requires flushing with water and removing contaminated clothes and jewelry. With a fire, people should first evacuate the lab. Once safe, they should close doors, pull the fire alarm, and call emergency services. Anyone who is on fire should stop, drop, and roll.

Explanation:

Because that is what you are supposed to do

3 0
3 years ago
g Using the complex based titration system: 50.00 mL 0.00250 M Ca2 titrated with 0.0050 M EDTA, buffered at pH 11.0 determine (i
kobusy [5.1K]

Answer:

Explanation:

a).

conc of Ca²⁺ =0.0025 M

pCa = -log(0.0025) = 2.6

logK,= 10.65 So lc = 4.47 x 10.

Formation constant of Ca(EDTA)]-z= 4.47 x 10¹⁰ At pH = 11, the fraction of EDTA that exists Y⁻⁴ is  \alpha_{Y^{-4}} =0.81

So the Conditional Formation constant= K_f =0.81x 4.47 x10¹⁰

=3.62x10¹⁰

b)

At Equivalence point:

Ca²⁺ forms 1:1 complex with EDTA At equivalence point,

Number of moles of Ca²⁺= Number of moles of EDTA Number of moles of Ca²⁺ = M×V = 0.00250 M × 50.00 mL = 0.125 mol

Number of moles of EDTA= 0.125 mol

Volume of EDTA required = moles/Molarity = 0.125 mol / 0.0050 M = 25.00 mL  

V e= 25.00 mL  

At equivalence point, all Ca²⁺ is converted to [CaY²⁻] complex. So the concentration of Ca²⁺ is determined by the dissociation of [CaY²⁻] complex.  

[CaY^{2-}] = \frac{Initial,moles,of, Ca^{2+}}{Total,Volume} = \frac{0.125mol}{(50.00+25.00)mL} = 0.001667M

                                                            {K^'}_f

                       Ca²⁺      +      Y⁴          ⇄     CaY²⁻

Initial                 0                  0                      0.001667

change             +x                  +x                     -x

equilibrium        x                    x                    0.001667 - x

{K^'}_f = \frac{[CaY^{2-}]}{[Ca^{2+}][Y^4]}=\frac{0.001667-x}{x.x} =\frac{0.001667-x}{x^2}\\\\x^2 = \frac{0.001667-x}{{K^'}_f}\\ \\

x^2=\frac{0.001667}{3.62\times10^{10}}=4.61\exp-14

x = 2.15×10⁻⁷

[Ca+2] = 2.15x10⁻⁷ M  

pca = —log(2 15x101= 6.7

3 0
3 years ago
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